Consider the reaction 2 al + Fe2O3 to 2Fe + Al2O3. If 60.0g of Al is reacted with excess Fe2O3, determine the amount (in moles)

Question

2 years ago

7

and mass (in grams) of Al2O3 produced

1 answer:

olganol [36] · Answer 1 · 2022-07-20T16:40:44+03:00

The amount of Al2O3 in moles= 1.11 moles while in grams = 113.22 grams

calculation

2 Al + Fe2O3 → 2Fe + Al2O3

step 1: find the moles of Al by use of moles= mass/molar mass formula

= 60.0/27= 2.22 moles

Step 2: use the mole ratio to determine the moles of Al2O3.

The mole ratio of Al : Al2O3 is 2: 1 therefore the moles of Al2O3= 2.22/2=1.11 moles

Step 3: finds the mass of Al2O3 by us of mass= moles x molar mass formula.

The molar mass of Al2O3 = (2x27) +( 16 x3) = 102 g/mol

mass is therefore= 102 g/mol x 1.11= 113.22 grams