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stepladder [879]
3 years ago
11

To which period does the Lanthanide series belong? Actinides?

Chemistry
1 answer:
borishaifa [10]3 years ago
7 0
Lanthanide belongs to period 6, and actinides belongs to period 7
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Describe an electron cloud. Then, name and explain a particular atomic model that used the concept of the electron cloud. (10 po
Blizzard [7]

Answer:

I hope this helped

Explanation:

1. A region with a high probability of containing electrons. An example is a simple atom, like Hydrogen.

2. Bohr's model of the atom, in which electrons circle the nucleus at fixed energy levels, cannot explain all the behaviors of electrons. Orbitals are the basis of the electron cloud model of the atom.

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Which choice tells the planet(s) that have an elliptical orbit(s) around the sun?
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A.Earth, Jupiter, and Mars
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Look at the diagram of an electrochemical cell below.
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Answer is: charges are balanced during redox.
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Water containing large amounts of Mg2+and Ca2+ions is said to be hard because it is hard to make soap lather in the water. True
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Answer:True

Explanation:

Water is said to be hard when it contains calcium ions or magnesium ions dissolved in it. These ions are able to react with soap in such a way that the soap is prevented from forming lather with the water. Hard water occurs when water passes over calcium or magnesium bearing minerals and dissolves some of it. Hardness due to the presence of calcium ions can easily be removed by boiling the water.

8 0
4 years ago
The half-life of tritium (H-3) is 12.3 years. If 48.0mg of tritium is released from a nuclear power plant during the course of a
Rudiy27

Answer:

The amount left after 49.2 years is 3mg.

Explanation:

Given data:

Half life of tritium = 12.3 years

Total mass pf tritium = 48.0 mg

Mass remain after 49.2 years = ?

Solution:

First of all we will calculate the number of half lives.

Number of half lives = T elapsed/ half life

Number of half lives =  49.2 years /12.3 years

Number of half lives =  4

Now we will calculate the amount left after 49.2 years.

At time zero 48.0 mg

At first half life = 48.0mg/2 = 24 mg

At second half life = 24mg/2 = 12 mg

At 3rd half life = 12 mg/2 = 6 mg

At 4th half life =  6mg/2 = 3mg

The amount left after 49.2 years is 3mg.

6 0
4 years ago
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