The "particles" of gases are actually atoms, or molecules. truefalse

An ethylene glycol solution contains 21.4 g of ethylene glycol (C2H6O2) in 97.6 mL of water. (Assume a density of 1.00 g/mL for

8090 [49]

Answer: The freezing point and boiling point of the solution are $-6.6^0C$ and $101.8^0C$ respectively.

Explanation:

Depression in freezing point:

$T_f^0-T^f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_f$ = freezing point of solution = ?

$T^o_f$ = freezing point of water = $0^0C$

$k_f$ = freezing point constant of water = $1.86^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(0-T_f)^0C=1\times (1.86^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_f=-6.6^0C$

Therefore,the freezing point of the solution is $-6.6^0C$

Elevation in boiling point :

$T_b-T^b^0=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of water = $100^0C$

$k_b$ = boiling point constant of water = $0.52^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(T_b-100)^0C=1\times (0.52^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_b=101.8^0C$

Thus the boiling point of the solution is $101.8^0C$

4 0

3 years ago

Which substance can not be decomposed by a chemical change?

slamgirl [31]

The answer is (2) Copper. Because copper is consist of atom. If it is decomposed, the atom will be changed. While chemical change is just the break down and form of chemical bonds between atoms.

6 0

2 years ago

In the reaction mg(s)+2hcl(aq) h2(g)+mgcl2(aq), how many grams of hydrogen gas will be produced from 125.0 ml of a 6.0m hcl in a

Kruka [31]

6.0m(mol/kg) of HCl
125mL H2O = 0.125kg
6mol/kg = n mol/0.125kg, n = 0.75mol
When 0.75mol of HCl reacts, 0.75/2=0.375mol of H2 is produced. H2 = 2g/mol
So, 0.375mol H2 = 0.75g

6 0

3 years ago

Read 2 more answers

Match these items.

mars1129 [50]

Here are the possible answers for the following questions above:
1. H-CC-H (name) - C. ethyne
2. cyclic compound with both saturated and unsaturated characteristics - G. benzene
3. CnH2n - E. general formula for alkenes
4. reaction typical of unsaturated hydrocarbons - A. addition
5. CnH2n-2 - F. general formula for alkynes
6. series name of hydrocarbons with triple bond - D. alkyne
7. CnH2n+2 - B. general formula of alkanes

6 0

3 years ago

Read 2 more answers

what is the specific heat of a substance if 1560 cal are required to raise the temperature of a 312-g sample by 15°C

jasenka [17]

Answer:

0.33 cal⋅g-1°C-1

Explanation:

The amount of heat required is determined from the formula:

q= mcΔT

To see more:

https://api-project-1022638073839.appspot.com/questions/what-is-the-specific-heat-of-a-substance-if-1560-cal-are-required-to-raise-the-t#235434

7 0

2 years ago