1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
algol [13]
3 years ago
14

What is the ph of a 0.15 m solution of ammonium chloride?

Chemistry
1 answer:
Thepotemich [5.8K]3 years ago
7 0
 Best Answer:  <span>(a) 
8.9 x 10^-7 = x^2 / 0.15-x 
x = [OH-] = 0.00037 M 
pOH = 3.4 
pH = 14 - 3.4 = 10.6 

(b) 
Ka = Kw/Kb = 5.6 x 10^-10 = x^2 / 0.20-x 
x = [H+] = 0.000011 M 
pH = 5.0</span>
You might be interested in
Which has a higher ionization energy: chlorine (Cl) or magnesium (Mg)? Why? Select the best answer
algol [13]

Removal of the loosely bounded electron is defined by the ionization energy. Chlorine needs less energy to add electrons and has higher ionization power. Thus, option A is correct.

<h3>What is ionization energy?</h3>

The ability of an electron to accept or give electrons to another element in a chemical reaction by forming and creating bonds and the positive and negative charges has been defined by the ionization energy.

Magnesium has lower ionization energy than chlorine due to its large size and smaller nuclear charge. On the other hand, chlorine can easily add electrons to the valence shell which is almost full.

Therefore, option A. chlorine has higher ionization energy and can add electrons with minimum energy.

Learn more about ionization energy here:

brainly.com/question/6842791

#SPJ1

3 0
1 year ago
Name three pure elements and three pure compounds​
VARVARA [1.3K]

Answer:

Pure elements:

Hydrogen(H)

Nitrogen(N)

Magnesium (Mg)

Pure Compounds:

Oxygen gas(O2)  

Water (H2O)  

Ammonia (NH3)

Explanation:

Hope it helps.Please mark me brainliest.^-^

5 0
3 years ago
HELP MEEEE!!!!!!!!!!!
Mekhanik [1.2K]

Answer:

The answer is A

Explanation:

That is the only answer that even remotely resembles an ultrasound hope this answered your question.

7 0
3 years ago
A student needs to prepare 100. mL of 0.612 M Cu(NO3)2 solution. What mass, in grams, of copper(II) nitrate should the student u
Temka [501]

Answer: 11.5 grams

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution

Molarity=\frac{n\times 1000}{V_s}

where,

Morality = 0.612 M

n= moles of solute  

V_s = volume of solution in ml = 100 ml

Now put all the given values in the formula of molarity, we get

0.612=\frac{n\times 1000}{100ml}

n=0.0612moles

Mass={\text {moles of solute }}{\times {\text {molar mass}}=0.0612moles\times 187.56g/mol=11.5g

Therefore, the mass of copper (II)nitrate required is 11.5 grams

3 0
3 years ago
Please help, any and all is very much appreciated!
iogann1982 [59]
1. True
2. False
3. False
4. True
5. True
6. True
7. All of the above
8. According to their reactivity with other substances
9. Standard temp and pressure
10. Flush your eyes in the eye flush for 15-20 minutes
3 0
3 years ago
Other questions:
  • What is the name of this hydrocarbon?
    10·2 answers
  • Can somebody give me a example of a mixture?
    11·2 answers
  • How does fire impact the various populations of trees?
    11·1 answer
  • In 4.0 years , 40.0 kilograms of elemnt a decays to 5.0 kilograms
    15·1 answer
  • What is the maximum volume of a 0.788 M CaCl2 solution that can be prepared using 85.3 g CaCl2?
    11·1 answer
  • You fill a rigid steel cylinder that has a volume of 20.0 L with nitrogen gas to a final pressure of 2.00 *10^4 Kpa at 28c How m
    8·2 answers
  • Which is a component of John Dalton’s atomic theory?
    10·2 answers
  • The period number of any element is equal to the number of its energy levels
    6·1 answer
  • Difference between insulin resistance and insulin sensitivity? with source and thank ​
    7·1 answer
  • Hi, Can someone help me with this question, please! It's due tonight!
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!