Answer:
1010 m
Explanation:
The following data were obtained from the question:
Height (h) of cliff = 500 m
Horizontal velocity (u) = 100 m/s
Horizontal distance (s) =?
Next we shall determine the time taken for the cannon ball to hit the ground. This can be obtained as follow:
Height (h) of cliff = 500 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
500 = ½ × 9.8 × t²
500 = 4.9 × t²
Divide both side by 4.9
t² = 500/4.9
Take the square root of both side
t = √(500/4.9)
t = 10.1 s
Finally, we shall determine the horizontal distance travelled by the cannon ball.
This can be obtained by using the following formula (s = ut) as illustrated below:
Horizontal velocity (u) = 100 m/s
Time (t) = 10.1 s
Horizontal distance (s) =?
s = ut
s = 100 × 10.1
s = 1010 m
Thus, the cannon ball was launched 1010 m away from the cliff.
Answer:
A principle of material science which expect that bunches of particles delivered by development of electrons adjust themselves in bunches (called "spaces") in attractive materials. The heading of attractive field at a point is the heading to which a free north shaft would move in the event that set at that point within the field.
Given what we know, we can confirm that the letter V is often used to describe the typical shape of a mountain valley, while stream bank and stream bed described the side and bottom of a stream respectively.
<h3>What terms do we use to described streams?</h3>
As shown in the question, there are many ways to describe the different parts of a stream. The side of the stream is referred to as the bank of the stream, along its entire length, while the stream bed is a term used to describe the bottom.
Therefore, we can confirm that the letter V is often used to describe the typical shape of a mountain valley, while stream bank and stream bed described the side and bottom of a stream respectively.
To learn more about streams visit:
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Answer:
Part a)
Part B)
percentage increase is
%
Explanation:
Part a)
As we know that the beat frequency is
after increasing the tension the beat frequency is decreased and hence the tension in string B will increase
So we have
Part B)
percentage increase in the tension of the string will be given as
now we have
so we have
so we have
percentage increase is
Answer:
0.05 V/m
Explanation:
For a uniform electric field, electric field strength and potential difference are related by
where
E is the electric field strength
is the potential difference
d is the distance between the two points
Here we have
So, the electric field strength is