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Keith_Richards [23]
3 years ago
7

When the temperature of a gas decreases at constant volume, its a. pressure increases. b. mass increases. c. pressure decreases.

d. particles move faster.
Physics
1 answer:
EastWind [94]3 years ago
5 0

Answer:

a. pressure increases

b. particles move faster

Explanation:

When the temperature of a gas at constant volume increases, it means the kinetic energy of the gas particles will also increase and this means that the particles will move at a faster speed.

Also, since the particles are moving faster, it means they will be hitting the walls of the container carrying the gas at a faster rate.

And the higher the force, the higher the Pressure.

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inertia

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A 10.0-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wi
Veronika [31]

A) 1.05 N

The power dissipated in the circuit can be written as the product between the pulling force and the speed of the wire:

P=Fv

where

P = 4.20 W is the power

F is the magnitude of the pulling force

v = 4.0 m/s is the speed of the wire

Solving the equation for F, we find

F=\frac{P}{v}=\frac{4.20 W}{4.0 m/s}=1.05 N

B) 3.03 T

The electromotive force induced in the circuit is:

\epsilon=BvL (1)

where

B is the strength of the magnetic field

v = 4.0 m/s is the speed of the wire

L = 10.0 cm = 0.10 m is the length of the wire

We also know that the power dissipated is

P=\frac{\epsilon^2}{R} (2)

where

R=0.350 \Omega is the resistance of the wire

Subsituting (1) into (2), we get

P=\frac{B^2 v^2 L^2}{R}

And solving it for B, we find the strength of the magnetic field:

B=\frac{\sqrt{PR}}{vL}=\frac{\sqrt{(4.20 W)(0.350 \Omega)}}{(4.0 m/s)(0.10 m)}=3.03 T

5 0
3 years ago
A 4.2-m-diameter merry-go-round is rotating freely with an angularvelocity of 0.80 rad/s. Its total moment of inertia is1760kgm2
ASHA 777 [7]

Answer

given,

mass of people = 65 kg

number of people =

diameter of the  merry-go-round = 4.2 m

radius = 2.1 m

angular velocity = 0.8 rad/s

moment of inertia =  1760 kg m²

Using the law of conservation of angular momentum, we have

                             L₁=  L₂

                          I₁ω₁ =I₂ω₂

                            I₁ω₁= ( I₁+ 4 m r²)ω²

                         ( 1760 x 0.8) = ( 1760 + 4 x 65 x 2.12)ω²

                         1408 = 2311.2 ω²

                         ω² = 0.609

                         ω  = 0.781 rad/s

b) If the people jump of the merry-go-round radially, they exert no torque.

hence,  it will not change the angular momentum of the merry-go-round. It will continue to move with the same   ω .

7 0
3 years ago
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