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2 years ago

Help me please Will give brainliest if correct (No links or spam)

Chemistry

2 answers:

Paraphin [41]2 years ago

7 0

Answer:

Dip one end of the blue litmus paper into the solution take it out if it turns red then its acidic.

silver

Hydrogen gas

carbon dioxide

beryllium

magnesium chloride

Sorry if any are wrong i tried

PtichkaEL [24]2 years ago

6 0

Answer:

Dip one end of the blue litmus paper into the solution take it out if it turns red then its acidic.

silver

Hydrogen gas

carbon dioxide

beryllium

magnesium chloride

Sorry if any are wrong i tried

Explanation:

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The heat of reaction for the combustion of propane is –2,045 kJ. This reaction is: C3H8(g) +502 (g) 3CO2 (g) + 4H2O (g). Determi

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Answer:

$\Delta _fH_{C_3H_8}=-102.7kJ/mol$

Explanation:

Hello,

In this case, we can consider that the given heat of combustion is indeed the heat of reaction since it corresponds to the combustion of propane, which is computed by using the heat formation of all the involved species as shown below:

$\Delta _cH=3*\Delta _fH_{CO_2}+4*\Delta _fH_{H_2O}-\Delta _fH_{C_3H_8}-5*\Delta _fH_{O_2}$

Thus, since the heat of formation of gaseous carbon dioxide is -393.5 kJ/mol, water -241.8 kJ/mol and oxygen 0 kJ/mol, the heat of formation of propane is:

$\Delta _fH_{C_3H_8}=3*\Delta _fH_{CO_2}+4*\Delta _fH_{H_2O}-5*\Delta _fH_{O_2}-\Delta _cH\\\\\Delta _fH_{C_3H_8}=3*(-393.5)+4*(-241.8)-5*0-(-2045)\\\\\Delta _fH_{C_3H_8}=-102.7kJ/mol$

Best regards.

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