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Goshia [24]
3 years ago
9

Help me please Will give brainliest if correct (No links or spam)

Chemistry
2 answers:
Paraphin [41]3 years ago
7 0

Answer:

Dip one end of the blue litmus paper into the solution take it out if it turns red then its acidic.

silver

Hydrogen gas

carbon dioxide

beryllium

magnesium chloride

Sorry if any are wrong i tried

PtichkaEL [24]3 years ago
6 0

Answer:

Dip one end of the blue litmus paper into the solution take it out if it turns red then its acidic.

silver

Hydrogen gas

carbon dioxide

beryllium

magnesium chloride

Sorry if any are wrong i tried

Explanation:

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A 100-g piece of metal initially at T = 75C is submerged in 100 g of water initially at T = 25C. The specific heat capacity of i
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I’m not so sure but I think it’s b
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4 years ago
You do an experiment in which you need 0.25 mole of tyrosine (C,H11 NO3).
Marina CMI [18]

Answer:

B.90.5 g

Explanation:

not 100%sure hehe

6 0
3 years ago
Summarize your findings in a short report of 150 words. Include your hypothesis, observations, data, calculations, and conclusio
Damm [24]

Answer:

Follow these steps.

1. Fill the matchbox with pebbles. Weigh the matchbox with the pebbles inside. Record that weight.

2. Tie the string to the box. Allow the string to hang over the edge of the table.

3. Tie the other end of the string to a corner of the plastic bag, leaving an opening to put in coins.

4. Add coins one by one until the box is pulled off the table.

5. Count and record the number of coins and the weight of the bag with the coins in it.

6. Lay the round sticks on the table about 1 inch apart and about 2 inches from the edge of the table.

7. Put the matchbox on the rollers farthest from the edge of the table.

8. Now add coins one by one to the bag until the box is pulled off the table.

9. Count and record the number of coins and the weight of the bag with the coins in it.

10. Repeat the experiment. Determine your margin of error if your results vary. For accuracy, repeat the experiment if desired.

11. Using the equation for the coefficient of friction in the text above, determine the coefficient of friction for the matchbox in each experiment. Include this data in your summary.

Explanation:

I think this is useful

please make me as breainlest

5 0
3 years ago
A 250.0 mL sample of aqueous solution contains an unknown amount of dissolved NaBr. Excess aqueous Pb(NO3)2is then added to this
Scrat [10]

Answer:

A. 0.0655 mol/L.

B. PbBr2.

C. Pb2+(aq) + Br- --> PbBr2(s).

Explanation:

Balanced equation of the reaction:

Pb(NO3)2(aq) + 2NaBr(aq) --> PbBr2(s) + 2NaNO3(aq)

A.

Number of moles

PbBr2

Molar mass = 207 + (80*2)

= 367 g/mol.

Moles = mass/molar mass

= 3.006/367

= 0.00819 mol.

Since 2 moles of NaBr reacted to form 1 mole of PbBr2. Therefore, moles of NaBr = 2*0.00819

= 0.01638 moles of NaBr.

Since, the ionic equation is

NaBr(aq) --> Na+(aq) + Br-(aq)

Since 1 moles of NaBr dissociation in solution to give 1 mole of Br-

Therefore, molar concentration of Br-

= 0.0164/0.25 L

= 0.0655 mol/L.

B.

PbBr2

C.

Pb(NO3)2(aq)--> Pb2+(aq) + 2No3^2-(aq)

2NaBr(aq) --> 2Na+(aq) + 2Br-(aq)

Net ionic equation:

Pb2+(aq) + 2Br- --> PbBr2(s)

8 0
3 years ago
Balloon X is filled with the carbon monoxide. Balloon Y is filled to the same volume with carbon dioxide. The balloons are left
weqwewe [10]

Answer:

The smallest ballon is the ballon X

Explanation:

It is possible to answer this question by using Graham's law:

\frac{v_1}{v_2} =\sqrt{\frac{MW_2}{MW_1}}

Where v is the speed of effusion and MW is molar weight of each compound.

This equation is showing that speed is inversely related to the square root of its molar mass. As carbon dioxide has a bigger MW than carbon monoxide, the speed of effusion of carbon dioxide is lower doing its ballon biggest than carbon monoxide ballon, thus: <em>The smallest ballon is the ballon X</em>

<em></em>

I hope it helps!

6 0
3 years ago
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