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stepan [7]
3 years ago
14

The reaction below can be catalyzed by bromine (Br2). if you carried out such a reaction, which compound would you expect to fin

d in the reaction container at the end of the reaction?
A) Br2
B) BrO
C) BrH2
D) BrO2
Chemistry
1 answer:
Vika [28.1K]3 years ago
3 0

The answer is Br₂ since catalysts are regenerated at the end of a reaction.

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Please help!<br><br> Fill in the blank
umka21 [38]

Answer:

carbon

Explanation:

3 0
3 years ago
The reaction of pyrrole with bromine forms predominantly __________. View Available Hint(s) The reaction of pyrrole with bromine
xenn [34]

Answer:

a) 2-bromopyrrole

Explanation:

Our options for this questions are:

a) 2-bromopyrrole

b) 2,3-dibromopyrrole

c) N-bromopyrrole

d) 3-bromopyrrole

To understand how the reaction works we have to start with the <u>resonance structures</u>. (Figure 1), on these structures, we will obtain a n<u>egative charge on carbon 2</u> in the pyrrole ring, therefore on this carbon we can generate an attack to an electrophile.

The second step is to check how the mechanism take place. An <u>electrophile is generated</u> by the Br_2 and FeBr_3. This electrophile can be <u>attacked</u> by the negative charge on carbon 2 producing the 2-bromopyrrole. (See figure 2).

I hope it helps!

5 0
3 years ago
Write a general word equation for a neutralization reaction.
xenn [34]
Hydrochloric acid + Sodium hydroxide =Sodium chloride +water
8 0
3 years ago
Nitrogen is made up of two nitrogen atoms. Therefore, nitrogen is a
In-s [12.5K]
The chemical element of atomic number 7, a colorless, odorless unreactive gas that forms about 78 percent of the earth's atmosphere.
5 0
2 years ago
Read 2 more answers
How many atoms are there in 0.32g of copper
aivan3 [116]

The number   of atoms that are in 0.32 g  of  copper  are

 3.01 x10^21  atoms


        <u><em>calculation</em></u>

<u><em>    </em></u>Step  1: find the number of moles  of Copper

       moles =  mass/molar  mass

      =  0.32  g /63.5  g/mol=0.005  moles

 Step  2:  use the Avogadro's  constant  to determine  the  number of  atom                

             in  0.005 moles of Cu

 that is   according to  Avogadro's  law   1 mole =6.02 x10^23 atoms

                                                                    0.005 moles=?  atoms

          by cross   multiplication

  =  (0.005  moles  x 6.02 x10^23 atoms) /  1 mole= 3.01 x10 ^21 atoms


7 0
2 years ago
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