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ElenaW [278]
3 years ago
6

Blank c2h4 + blank o2 → blank co2 + blank h2o how many moles of o2 are in the chemical equation when balanced using the lowest w

hole numbers
Chemistry
1 answer:
umka21 [38]3 years ago
8 0

The reaction is<span>
C</span>₂H₄ + O₂ → CO₂ + H₂O<span>

To balance the equation, both side have same number of elements. Here,</span>

In left hand side has                                            in right hand side has

           4 H atoms                                                       2 H atoms 

           2 C atoms                                                       1 C atom 

<span>           2 O atoms                                                       3 O atoms 

First, we have to balance number of C atoms and number of H atoms in both side.  
To balance C atoms, '2' should be added before CO</span>₂ and to balance H atoms, '2' should be added before H₂<span>O. 
Then number of oxygen atoms is </span>2 x 2 + 2 = 6 in right hand side. So, 3 should be added before O₂<span> in left hand side.
After balancing the equation should be,</span>

C₂H₄<span> + 3O</span>₂<span> → 2CO</span>₂<span> + 2H</span>₂O


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As the ball falls, its energy will decrease and its energy will increase
svlad2 [7]

Answer: As an object falls its potential energy decreases, while its kinetic energy increases. The decrease in potential energy is exactly equal to the increase in kinetic energy.

Explanation:

4 0
3 years ago
PLEASE HELP I'M STUCK
Leona [35]

F=Ma

F=52000N

M=1060kg

a=F/M

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6 0
3 years ago
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At a certain temperature this reaction follows first-order kinetics with a rate constant of 0.086 s^-1:
tankabanditka [31]

It takes 31 s for 1.27 M H₃PO₄ to decrease its concentration to 7.0% of its initial value following first-order kinetics.

<h3>What is first-order kinetics?</h3>

First-order kinetics occur when a constant proportion of a reactant disappears per unit time.

Let's consider the following first-order kinetics reaction with a rate constant k = 0.086 s⁻¹.

2 H₃PO₄(aq) = P₂O₅(aq) + 3 H₂O(aq)

Given the initial concentation is [H₃PO₄]₀ = 1.27 M, the concentration representing 7.0% of this value is:

[H₃PO₄] = 7.0% × 1.27 M = 0.089 M

We can calculate the time elapsed (t) using the following expression.

ln ([H₃PO₄]/[H₃PO₄]₀) = - k × t

ln (0.089 M/1.27 M) = - 0.086 s⁻¹ × t

t = 31 s

It takes 31 s for 1.27 M H₃PO₄ to decrease its concentration to 7.0% of its initial value following first-order kinetics.

Learn more about first-order kinetics here: brainly.com/question/18916637

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8 0
2 years ago
What is the half-life of polonium-210 if it takes 828 days for a sample to be reduced to 1.6% of its original mass?
vagabundo [1.1K]

Answer:

The half-life of polonium-210 is approximately 138.792 days.

Explanation:

We must remember that the decay of a radioisotope is modelled by this ordinary differential equation:

\frac{dm}{dt} = -\frac{m(t)}{\tau}

Where:

m(t) - Current mass of the isotope, measured in grams.

\tau - Time constant, measured in days.

Whose solution is:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where m_{o} is the initial mass of the isotope, measured in grams.

Our first step is to determine the value of the time constant:

-\frac{t}{\tau} = \ln \frac{m(t)}{m_{o}}

\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }

If we know that \frac{m(t)}{m_{o}} = 0.016 and t = 828\,days, then the time constant of the radioisotope is:

\tau = -\frac{828\,days}{\ln 0.016}

\tau \approx 200.234\,days

And lastly we find the half-life of polonium-210 (t_{1/2}), measured in days, by using this expression:

t_{1/2} = \tau \cdot \ln 2

t_{1/2} = (200.234\,days)\cdot \ln 2

t_{1/2}\approx 138.792\,days

The half-life of polonium-210 is approximately 138.792 days.

4 0
2 years ago
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maria [59]
<span>Soil and water is a suspension because it consists of larger particles suspended in the medium, which start to settle when allowed to stand. Milk is a colloid because it consists of minute particles that remain suspended in the medium. Hope I helped! Please mark as brainliest, to help me out. :)</span>
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3 years ago
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