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ElenaW [278]
3 years ago
6

Blank c2h4 + blank o2 → blank co2 + blank h2o how many moles of o2 are in the chemical equation when balanced using the lowest w

hole numbers
Chemistry
1 answer:
umka21 [38]3 years ago
8 0

The reaction is<span>
C</span>₂H₄ + O₂ → CO₂ + H₂O<span>

To balance the equation, both side have same number of elements. Here,</span>

In left hand side has                                            in right hand side has

           4 H atoms                                                       2 H atoms 

           2 C atoms                                                       1 C atom 

<span>           2 O atoms                                                       3 O atoms 

First, we have to balance number of C atoms and number of H atoms in both side.  
To balance C atoms, '2' should be added before CO</span>₂ and to balance H atoms, '2' should be added before H₂<span>O. 
Then number of oxygen atoms is </span>2 x 2 + 2 = 6 in right hand side. So, 3 should be added before O₂<span> in left hand side.
After balancing the equation should be,</span>

C₂H₄<span> + 3O</span>₂<span> → 2CO</span>₂<span> + 2H</span>₂O


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Burka [1]

Answer:

\large \boxed{\text{E) 721 K; B) 86.7 g}}

Explanation:

Question 7.

We can use the Combined Gas Laws to solve this question.

a) Data

p₁ = 1.88 atm; p₂ = 2.50 atm

V₁ = 285 mL;  V₂ = 435 mL

T₁ = 355 K;     T₂ = ?

b) Calculation

\begin{array}{rcl}\dfrac{p_{1}V_{1}}{T_{1}}& =&\dfrac{p_{2}V_{2}}{T_{2}}\\\\\dfrac{1.88\times285}{355} &= &\dfrac{2.50\times 435}{T_{2}}\\\\1.509& = &\dfrac{1088}{T_{2}}\\\\1.509T_{2} & = & 1088\\T_{2} & = & \dfrac{1088}{1.509}\\\\ & = & \textbf{721K}\\\end{array}\\\text{The gas must be heated to $\large \boxed{\textbf{721 K}}$}

Question 8. I

We can use the Ideal Gas Law to solve this question.

pV = nRT

n = m/M

pV = (m/M)RT = mRT/M

a) Data:

p = 4.58 atm

V = 13.0 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 385 K

M = 46.01 g/mol

(b) Calculation

\begin{array}{rcl}pV & = & \dfrac{mRT}{M}\\\\4.58 \times 13.0 & = & \dfrac{m\times 0.08206\times 385}{46.01}\\\\59.54 & = & 0.6867m\\m & = & \dfrac{59.54}{0.6867 }\\\\ & = & \textbf{86.7 g}\\\end{array}\\\text{The mass of NO$_{2}$ is $\large \boxed{\textbf{86.7 g}}$}

7 0
3 years ago
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Answer:

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A reaction rate essay is a laboratory method to determine the activity of an enzyme. It is necessary for determining the enzyme kinetics and inhibition.

Whereas, a colorimetric analysis is a method to determine the concentration of a chemical compound in a solution. Therefore, a colorimetric endpoint assay measures the concentration.

Therefore, Enzyme activity is measured by a reaction rate assay and the concentration is measured by a colorimetric endpoint assay.

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