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professor190 [17]
3 years ago
11

HELP PLEASE ............

Physics
1 answer:
Liono4ka [1.6K]3 years ago
7 0
1. solid
2. The molecules are tightly packed together so tha means there is less movement between the molecules.
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Could someone help me with this question please?
BabaBlast [244]
You are correct...amplitude will be the answer
3 0
3 years ago
Read 2 more answers
Wнιcн parт oғ тнe eхaмple repreѕenтѕ heat
PtichkaEL [24]
I would think something like fire or a torch because that seems like it means heat or maybe a campfire picture
3 0
3 years ago
The experimental apparatus shown in the figure above contains a pendulum consisting of a 0.66 kg ball attached to a string of le
lara31 [8.8K]

The problem is solved and the questions are answered below.

Explanation:

a. To calculate the speed of the 0.66 kg ball just before the collision

V₀ + K₀ = V₁ + K₁

= mgh₀ = 1/2 mv₁²

where, h= r - r cosθ

V = \sqrt{2gh}

 V = 2.42 m/s

b. Calculate the speed of the 0.22 kg ball immediately after the collision

y = y₀ + Vy₀t - 1/2 gt²

0 = 1.2 - 1/2 gt²

t = 0.495 s

x = x₀ + Vx₀t

1.4 = 0 + vx₀ (0.495)

Vx₀ = 2.83 m/s

C. To Calculate the speed of the 0.66 kg ball immediately after the collision

m₁ v₁ = m₁ v₃ + m₂ v₄

(0.66)(2.42) = (0.66) v₃ + (0.22)(2.83)

V₃ = 1.48 m/s

D. To Indicate the direction of motion of the 0.66 kg ball immediately after the collision is to the right.

E. To Calculate the height to which the 0.66 kg ball rises after the collision

V₀ + k₀ = V₁ + k₁

1/2 mv₀² = mgh₁

h₁ = v₀²/2 g

  = 0.112 m

F. Based on your data, No the collision is not elastic.

Δk = 1/2 m₁v₃² =1/2 m₂v₄² - 1/2 m₁v₁²

     = 1/2 (0.66)(1.48)² + 1/2 (0.22)(2.83)² - 1/2 (0.66)(2.42)²

    = - 0.329 J

Hence, kinetic energy is not conserved.

8 0
3 years ago
The maximum current output of a 60 Ω circuit is 11 A. What is the rms voltage of the circuit?
ICE Princess25 [194]

Answer:

660V

Explanation:

V=IR

V=?,I=11A,R=60w

V=60×11

=660V

3 0
3 years ago
Someone please help? :)
Gnoma [55]

Answer:

(A) F_N - mg\cos\theta

Explanation:

The net force perpendicular to the surface of the incline is the sum of the gravity force component, which is mgcos(theta), and the reactionary normal force caused by the surface of the incline. The sum is F_N - mgcos(theta) and is usually 0 which is why the object is not moving perpendicularly to the surface of the incline.

8 0
3 years ago
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