Work Done = Force x Distance Moved
Work Done = 25 x 15 = 375 Joules
<span>D. density is your answer</span>
His is a step down transformer since n(primary) is greater than n(seconcary). You relate the input voltage with the ouput voltage with the following equation:
<span>Vout = n2/n1*Vin (n2/n1 is essentially your 'transfer function' that dictates what a specified input would produce) </span>
<span>Solving the equation: </span>
<span>Vin = Vout*n1/n2 = (320V)*(600/300) = 640 V </span>
<span>This is checked by seeing if Vin is greater than Vout, which it is for a step down transformer.</span>
Answer:
A
Explanation:
Wattage = E * I
E = 25
I = 5
Wattage = 25 * 5
Wattage = 125
The secondary, in an ideal transformer has the same wattage.
125 = 50 * I Divide by 50
125/50 = I
I = 2.5