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3 years ago

What is -7x+3y=-24+7x -2x+5y=-11

1 answer:

7 0

-7x+3y=-24+7x-2x+5y
-7x+3y=5x+5y-24
-12x-2y=-24

-7x+3y=-11

-36x-6y=-72
-14x+6y=-22
-50x=-94
Okay well I did something wrong

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They both are congruent

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(PICTURE) Can someone please help me out Im reporting trolls. Marking brainliest

Goshia [24]

Answer:

smart dot company would be c=.50t+12

communication plus would be c=2.50t

Step-by-step explanation:

smart dot starts with $12 a month and adds $0.50 for each hour of internet use. communication plus has no starting fee so it just adds $2.50 for each hour of internet use.

So then for the table you would put the number given for time in for the letter t and find what c would be. This would then find your cost for that amount of hours. To get you started smart dot company starts off with 0 hours so put that in for t being c=0.50(0)+12 and c=12. Communication plus also starts with 0 so it would be c=2.50(0) and c=0

Then you graph once you have both values you can graph having x=time and y=cost

Let me know if this helps!

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3 years ago

Using f (x) = 4x + 3 and g(x) = x - 2, f(g(5))=

il63 [147K]

Answer:

I think It is 7

Step-by-step explanation:

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2 years ago

Which of the following expressions is equivalent to a3 + b3?

lubasha [3.4K]

ANSWER
${a}^{3} + {b}^{3} = (a + b)( {a}^{2 } - ab + {b}^{2} )$

EXPLANATION

To find the expression that is equivalent to
${a}^{3} + {b}^{3}$
we must first expand
${(a + b)}^{3}$
Then we rearrange to find the required expression.

So let's get started.

${(a + b)}^{3} = (a + b) {(a + b)}^{2}$

We expand the parenthesis on the right hand side to get,

${(a + b)}^{3} = (a + b) ( {a}^{2} + 2ab + {b}^{2} )$

We expand again to obtain,

${(a + b)}^{3} = {a}^{3} + 3 {a}^{2}b + 3a {b}^{2} + {b}^{3}$

Let us group the cubed terms on the right hand side to get,

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2}b + 3a {b}^{2}$

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab (a+ b)$

We make the cubed terms the subject,

${(a + b)}^{3} - 3ab (a+ b) = {a}^{3} + {b}^{3}$

We factor to get,

$(a + b)({(a + b)}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We expand the bracket on the left hand side to get,

$(a + b)( {a}^{2} + 2ab + {b}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We finally simplify to get,

$(a + b)( {a}^{2} - ab + {b}^{2} ) = {a}^{3} + {b}^{3}$

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Im need help on this question

dimulka [17.4K]

You were right, its the second choice CA=CB+BA

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