Answer:
When the air pressure in the throat and outside the body is less than the air pressure in the middle ear, barotrauma occurs.
Explanation:
Ear barotrauma is a medical condition that describes discomfort in the ear which is caused by pressure differences in the inner and outer ear drum.
Usually, the air pressure in the middle ear is the same as the air pressure in the throat and outside the body.
When we swallow, the eustachian tube opens up and air flows out of and into the middle ear, this balances the pressure. But if the eustachian tube is blocked, the air pressure in the throat and outer body become different from the air pressure in the middle ear.
Answer:
L/2
Explanation:
Neglect any air or other resistant, for the ball can wrap its string around the bar, it must rotate a full circle around the bar. This means the ball should be able to swing to the top position where it's directly above the bar. By the law of energy conservation, this happens when the ball is at the same level as where it's previously released vertically. It means the swinging radius around the bar must be at least half of the string length.
So the distance d between the bar and the pivot should be at least L/2
<em>If the force squeezing two surfaces together is decreased, the force of dry sliding friction between the two surfaces will most likely decrease. </em>
<u>therefore your answer is B)</u><u>d</u><u>e</u><u>crease </u>
Hope this helps you- have a good day bro cya)
Answer:
d. According to the previous theorem:
(kh^2)/2-mgh-(m(2v)^2)/2=0,
126h^2-2.577h-8.236=0,
h=0.266 m.
Explanation:
