<span>On what:
f (is the focal length of the lens) = ?
p (is the distance from the object to the lens) =15.8 cm
p' (is the distance from the image to the spherical lens) = 4.2 cm
</span><span>Using the Gaussian equation, to know where the object is situated (distance from the point).
</span>




Product of extremes equals product of means:



Answer:
5.78amps
Explanation:
Given data
Time t= 57 seconds
Charge Q= 330C
Current I= ??
The expression for the electric current is given as
Q= It
Substituting we have
330= I*57
I= 330/57
I=5.78 amps
Hence the current is 5.78amps
Answer:
A) 
B) F = 1632.65 N
Explanation:
Given details
outside air speed is given as 
since inside air is atmospheric , 
a) By using bernoulli equation between outside and inside of flight


![\Delta P = \frac{1}{2} \rho[ v_2^2 -v_1^2]](https://tex.z-dn.net/?f=%5CDelta%20P%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Crho%5B%20v_2%5E2%20-v_1%5E2%5D)
![\Delta P = \frac{1}{2} 1.29 [ 150^2 - 0^2]](https://tex.z-dn.net/?f=%5CDelta%20P%20%3D%20%5Cfrac%7B1%7D%7B2%7D%201.29%20%5B%20150%5E2%20-%200%5E2%5D)

b) force exerted on window
Area of window 
We know that force is given as


F = 1632.65 N
Answer:
<em>Fn = 50 N</em>
Explanation:
<u>Net Force</u>
The net force is the sum of all the forces acting on an object.
When all the forces act in a single line, the direction of the forces is given by their signs. Positive signs are assumed to be up and left on both axes.
The box being raised by a force has a weight of W=-125 N. The negative sign indicates the weight points down. The accelerating force goes up and its value is F=175 N. The positive sign indicates this force pushes the box up.
The forces acting on the box are:
The weight W=-125 N
The accelerating force F=175 N
The net force is
Fn = W + F = -125N + 175 N
Fn = 50 N