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Lelu [443]
4 years ago
10

The primary coil of a transformer has 225 turns and secondary coil has 1800 turns. The potential difference in the primary coil

is 250 V and the power input is 3 600 W.
PLEASE SHOW ALL STEPS!

a) Is this a step-up or step-down transformer?
b) What is the current in the primary coil?
c) What is the power in the secondary coil?
d) What is the potential difference in the secondary coil? e) What is the current in the secondary coil?
Physics
1 answer:
Crank4 years ago
4 0

Answer:

Explanation:

a )  Since number of turns in secondary is more than that in primary so it is step up transformer.

b ) power in input = 3600W

Current x potential of primary = power

current = power / potential of primary

= 3600 / 250

= 14.4 A .

c ) power of secondary = power of primary = 250 W.

d ) potential diff of secondary = (1800 / 225) x 250

= 2000V .

e ) current in secondary

= power in secondary / potential in secondary

= 3600 / 2000

= 1.8 A.

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Car A has a mass of 1,200 kg and is traveling at a rate of 22 km/hr. It collides with car B. Car B has a mass of 1,900 kg and is
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The car B has the mass of 1900 kg.

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The car B has the velocity of 25 Km/hr.

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Let the velocity of cars A and B are denoted as v_{1} \ and\ v_{2}

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                                                  p_{i} =m_{1} v_{1} +m_{2} v_{2}

[Here p stand for momentum.]

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As per law of conservation of linear momentum the sum total linear momentum for an isolated system is always constant.Hence irrespective of the type of collision[elastic and inelastic],the momentum of the system is always constant which is a universal truth.

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                              p_{i} =p_{f}

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7 0
3 years ago
Read 2 more answers
39 g aluminum spoon (specific heat 0.904 J/g·°C) at 24°C is placed in 166 mL (166 g) of coffee at 83°C and the temperature of th
tatuchka [14]

<u>Answer:</u> The final temperature of the solution is 80.14^oC

<u>Explanation:</u>

The amount of heat released by coffee will be absorbed by aluminium spoon.

Thus, \text{heat}_{absorbed}=\text{heat}_{released}

To calculate the amount of heat released or absorbed, we use the equation:  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

Also,

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]    ..........(1)

where,

q = heat absorbed or released

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m_2 = mass of coffee = 166 g

T_{final} = final temperature = ?

T_1 = temperature of aluminium = 24^oC

T_2 = temperature of coffee = 83^oC

c_1 = specific heat of aluminium = 0.904J/g^oC

c_2 = specific heat of coffee= 4.1801J/g^oC

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T_{final}=80.14^oC

Hence, the final temperature of the solution is 80.14^oC

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