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-Dominant- [34]
3 years ago
7

Professional baseball pitchers deliver pitches that can reach the blazing speed of 100 mph (miles per hour). A local team has dr

afted an up-and-coming, left-handed pitcher who can consistently pitch at 42.91 m/s (96.00 mph) . Assuming a pitched ball has a mass of 0.1434 kg and has this speed just before a batter makes contact with it, how much kinetic energy does the ball have?
Physics
1 answer:
maria [59]3 years ago
5 0

Answer: 132.02 J

Explanation:

By definition, the kinetic energy is written as follows:

KE = 1/2 m v²

In our question, we know from the question, the following information:

m = 0.1434 Kg

v= 42.91 m/s

Replacing in the equation for KE, we have:

KE = 1/2 . 0.1434 Kg. (42.91)² m²/s² ⇒ KE = 132.02 N. m = 132.02 J

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A projectile is fired directly upwards at 49.4 m/s. A second projectile is dropped from rest at some higher elevation at the ins
8090 [49]

Answer:

Explanation:

velocity of first projectile after 3 s

v = u - gt

v = 49.4 - 9.8 x 3

= 20 m /s

Velocity of second projectile after 3 s after being dropped from rest

v = u + gt

= 0 + 9.8 x 3

= 29.4 m /s

They will be moving in opposite direction at the time of meeting , so their relative velocity

= 20 + 29.4 = 49.4 m /s

From the frame of reference of the first projectile, the velocity of the second projectile will be 49.4 m /s .

8 0
2 years ago
A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = 0.01t4 − 0.0
ivolga24 [154]
Since you solved a and b I will start with part c.
Part C
To answer this question we need to find zeros of a velocity function:
v(t)=0.04t^3-0.06t^2
We can factor this polynomial:
v(t)=0.04t^3-0.06t^2=t^2(0.04t-0.06)
Now it's pretty easy to find zeros. This function will be equal to zero when any of the factors are equal zero. 
t^2=0;\\ 0.04t-0.06=0
We solve these two equations and we get our zeros:
t_1=0; t_2=\frac{3}{2}
The particle is at rest at t=0 and t=3/2.
Part D
To solve this we need to determine when our velocity function is greater than zero. We will use factored form. 
We determine when each factor is greater than zero and with that information, we build the following table:
\centering \label{my-label} \begin{tabular}{lllll} Range & -\infty & 0 & 3/2 & +\infty \\ t^2 & - & + & + & + \\ 0.04t-0.06 & - & - & + & + \\ t^2 (0.04t-0.06) & + & - & + & + \end{tabular}
We can see, from the table, that our function is positive when - \infty < t and t>3/2.
That is the range in which particle is moving in positive direction.
Part E
We know that distance traveled is given with:
s(t)=0.01t^4 - 0.02t^3
We simply plug in t=12 to find total distance traveled:
s(12)=0.01(12)^4 - 0.02(12)^3=172.80 ft
Part F
We know that acceleration is defined as a rate of change of velocity.
We find acceleration by taking the first derivative of velocity with respect to time.
a(t)=\frac{dv}{dt}=(0.04t^3-0.06t^2)'=0.12t^2-0.12t
To find acceleration after 1 second we simply plug in t=1s in above equation:
a(1)=0.12-0.12=0


7 0
3 years ago
Which of the following represents a virtual image?
erma4kov [3.2K]
The answer for Apex is D. 
3 0
3 years ago
Read 2 more answers
A wave travels at a constant speed. How does the wavelength change if the frequency is reduced by a factor of 4?
Svetlanka [38]

Answer:

The product of (wavelength) x (frequency) is always the same number ... the wave's speed.  

So if the wavelength is somehow reduced to  1/4  its original length, the frequency is immediately multiplied by 4 .  That's the only way their product can remain the same.

Explanation:

5 0
3 years ago
How would these two particle diagrams be classified?
LekaFEV [45]

Answer:

A-) Both are pure substances each containing one type of compound

4 0
2 years ago
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