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Gemiola [76]
4 years ago
7

What are positive effects of plastics?

Physics
2 answers:
IRISSAK [1]4 years ago
4 0

Answer:

Explanation:

Plastic can be used for various purposes due to the fact that it can be molted into different shapes and sizes. It is a good packaging and transport material. Due to it's sterile nature does not support microbial growth thus used in healthcare items. It is inexpensive and can be affordable by all.

tamaranim1 [39]4 years ago
3 0
<span>It is light, easily shaped, strong, and inexpensive. Its ability to guard against contamination makes it useful in sterile medical environments such as hospitals.</span>
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Encoding information occurs throughout forming memory and is the first step of the memory process.
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4 years ago
What is another term for weak solutions?
bezimeni [28]

Answer:

c

Explanation:

diluted means weakened

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3 years ago
What rock is formed by metamorphosing shale?
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The rock that is formed by metamorphosing shale is slate.

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If the Sun were to collapse into a black hole, the point of no return for an investigator would be approximately 3 km from the c
Marysya12 [62]

Answer:

1.97*10⁴N .He cannot survive.

Explanation:

The<em> </em><em>Tidal force</em> can be defined as the difference in force between center of  two bodies like center of earth and other bodies.This force stretches  the body too and fro from the center of mass of another body due to the difference in the gravitational force.

The tidal force is responsible for various phenomena like ocean tides,celestial body tearing up.

The tidal force is the effect of massive body gravitationally affecting another body.

The tidal force is the difference between the gravitational force of two bodies and directly proportional to the mass of body affecting another body and inversely proportional to the square of radius of the distance between center and the object.

Here let us consider height of person as 2m and d=1m

  ΔF=\frac{GMm}{(R-d)^{2} } -\frac{GMm}{(R+d)^{2} }

       =GMm[\frac{1}{(R-d)^{2} }-\frac{1}{(R+d)^{2} }]

         =(6.67*10⁻¹¹)(1.99*10³⁰)(1.0)[\frac{1}{(300*10^3-1)^{2} }-\frac{1}{(300*10^3+1)^{2} }}

   ΔF=1.97*10⁴N.

Thus he cannot survive

           

4 0
3 years ago
Two ropes are attached to a 40-kg object. The first rope applies a force of 50 N and the second, 40 N. If the two ropes are perp
Montano1993 [528]

To solve this problem we will use the concepts related to the resulting Vector Force product of two components, that is,

|\vec{F}| = \sqrt{F_x^2+F_y^2}

If we take the Force of 50 N as the force in the X direction and the Force of 40 N in the Y direction we will have to:

|\vec{F}| = \sqrt{F_x^2+F_y^2}

|\vec{F}| = \sqrt{(50)^2+(40)^2}

|\vec{F}| = 64.03N

Finally, since Newton's second law, acceleration can be determined as

F = ma

a = \frac{F}{m}

a = \frac{ 64.03}{40}

a = 1.6m/s^2

Therefore the resultant magnitude of the acceleration of the object is 1.6m/s^2

4 0
4 years ago
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