Answer:
F = 7.143 kN
Explanation:
given,
time taken to apply break = 1.05 s
car slows down from 15 m/s to 9 m/s
mass of the car = 1250 Kg
force is equal to the change in momentum with respect to time.
F = -7142.85 N
F = - 7.143 kN
Force is acting opposite direction of velocity of car i.e. the sign is negative.
Answer:
Charge on Moon and Earth is 5.43x10¹³ C .
Explanation:
Gravitational force is the force of attraction between any two bodies having mass while Electrostatic force is the force experienced by two charge bodies. Electrostatic force can be attractive or repulsive.
Let M and m be the mass of Earth and Moon respectively, d is the distance between Earth and Moon and q be the charge on Earth and -q be on the Moon.
Gravitational force, F₁ =
Here G is gravitational constant.
Electrostatic force, F₂ =
Here k is Coulomb constant.
According to the problem, the gravitational force between Earth and Moon is equal to the electrostatic force between them.
F₁ = F₂
=
=
Put 6.07x10⁻¹¹ N m²/kg² for G, 5.97x10²⁴ kg for M, 7.34x10²² kg for m and 9x10⁹ N m²/C² in the above equation.
= q²
q =
q = 5.43x10¹³ C
The food you eat every day provides the nutrients you need to survive. These food components include the macronutrients – protein, carbohydrate and fat – that offer calories as well as play specific roles in maintaining your health. Micronutrients, such as vitamins and minerals, don’t act as an energy source but do serve a variety of critical functions to ensure your body operates as optimally as possible.
Lighting is the static electricity stored in the clouds that is disposed to the earth.
Answer:
<u>Given the </u><u>equation of the particle</u><u>, we know that</u>:
a) In we evaluate in the former equation:
In
a) <u>So, we know that the </u><em><u>displacement</u></em><u> of te particle is given by:</u>
<u>To find it's </u><em><u>velocity, </u></em><u>we need to derivate the equation of position by the formula:</u>
<u>And </u><u>evaluate</u><u> this expression at each specified </u><u><em>t:</em></u>
b)
c)
d)
e)
<u>To find it's </u><u><em>acceleration</em></u><u>, we need to derivate the equation of velocity by the formula: </u>
<u></u>
<u>And </u><u>evaluate </u><u>this expression at each specified </u><em><u>t:</u></em>
f)
g)
h)
i)