Ming drives across Arizona in the middle of July. She drives for two hours in the hot, desert sun before stopping for

Which inference about Arthur is supported by the text?

yarga [219]

There is no picture

8 0

3 years ago

Stars of spectral type A and F are considered ________.

LekaFEV [45]

Answer:

B. the stars of spectral type A and F are considered reasonably to have habitable planets but much less likely to have planets with complex plant - or animal - like life.

Explanation:

The appropriate spectral range for habitable stars is considered to be "late F" or "G", to "mid-K" or even late "A". This corresponds to temperatures of a little more than 7,000 K down to a little less than 4,000 K (6,700 °C to 3,700 °C); the Sun, a G2 star at 5,777 K, is well within these bounds. "Middle-class" stars (late A, late F, G , mid K )of this sort have a number of characteristics considered important to planetary habitability:

• They live at least a few billion years, allowing life a chance to evolve. More luminous main-sequence stars of the "O", "B", and "A" classes usually live less than a billion years and in exceptional cases less than 10 million.

• They emit enough high-frequency ultraviolet radiation to trigger important atmospheric dynamics such as ozone formation, but not so much that ionisation destroys incipient life.

• They emit sufficient radiation at wavelengths conducive to photosynthesis.

• Liquid water may exist on the surface of planets orbiting them at a distance that does not induce tidal locking.

Thus , the stars of spectral type A and F are considered reasonably to have habitable planets but much less likely to have planets with complex plant - or animak - like life.

4 0

2 years ago

What may result when the energy that builds up at plate boundaries is released because the plates suddenly overcome the force of

Arlecino [84]

It has to be Earthquake

4 0

2 years ago

Read 2 more answers

wo parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the magnitude

melisa1 [442]

Answer:

-18896.49 V/m

Explanation:

Distance between the two plates = 10 cm = 10 x $10^{-2}$ m = 0.1 m

Also, one of the plates is taken as zero volt.

a. The potential strength between the zero volt plate, and 7.05 cm (0.0705 m) away is 393 V

b. The potential strength between the other plate, and 2.95 cm (0.0295 m) away is 393 V

Potential field strength = -dV/dx

where dV is voltage difference between these points,

dx is the difference in distance between these points

For the first case above,

potential field strength = -393/0.0705 = -5574.46 V/m

For the second case ,

potential field strength = -393/0.0295 = -13322.03 V/m

Magnitude of the field strength across the plates will be

-5574.46 + (-13322.03) = -5574.46 + 13322.03 = -18896.49 V/m

6 0

3 years ago

A 50 kg archer standing on frictionless ice shoots a 100g arrow at a speed of 100 m/s what uis the recoild pseed of the archer?

nexus9112 [7]

Answer:

v= 0.2 m/s

Explanation:

Given that

m₁ = 50 kg

m₂ = 100 g = 0.1 kg

u =10 0 m/s

If there is no any external force on the system then the total linear momentum of the system will be conserve.

Initial linear momentum = Final momentum

m₁u₁ + m₂ u₂ =m₂ v₂ +m₁v₁

50 x 0 + 0.1 x 100 = 50 v + 0

0+ 10 = 50 v

$v=\dfrac{10}{50}\ m/s$

v= 0.2 m/s

Therefore the recoil speed will be 0.2 m/s.

7 0

2 years ago