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3 years ago

How does object float

2 answers:

7 0

As you may know some objects float others do not, this is because some objects contain air or oxygen. for example an orange with a peel floats because the peal contains oxygen and an orange without a peel sinks because it does not contain air at oxygen

olchik [2.2K]3 years ago

6 0

The object float under only one condition: its density is less than density of liquid. Metal ships can float just because it's mass divided by displaced volume (which in fact equals density) is less than water.

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Are you better off in an accident where the hood is

horsena [70]

Answer:

you would be better off if the car bounced backwards

Explanation:

because if the hood was dismembered than you have a high chance of very bad injury but if it is just bounced back you would have less chance of getting hurt if properly sitting and seat belted.

5 0

3 years ago

Suppose that a comet that was seen in 550 A.D. by Chinese astronomers was spotted again in year 1941. Assume the time between ob

pickupchik [31]

To solve the problem it is necessary to apply the concepts related to Kepler's third law as well as the calculation of distances in orbits with eccentricities.

Kepler's third law tells us that

$T^2 = \frac{4\pi^2}{GM}a^3$

Where

T= Period

G= Gravitational constant

M = Mass of the sun

a= The semimajor axis of the comet's orbit

The period in years would be given by

$T= 1941-550\\T= 1391y(\frac{31536000s}{1y})\\T=4.3866*10^{10}s$

PART A) Replacing the values to find a, we have

$a^3= \frac{T^2 GM}{4\pi^2}$

$a^3 = \frac{(4.3866*10^{10})^2(6.67*10^{-11})(1.989*10^{30})}{4\pi^2}$

$a^3 = 6.46632*10^{39}$

$a = 1.86303*10^{13}m$

Therefore the semimajor axis is $1.86303*10^{13}m$

PART B) If the semi-major axis a and the eccentricity e of an orbit are known, then the periapsis and apoapsis distances can be calculated by

$R = a(1-e)$

$R = 1.86303*10^{13}(1-0.997)$

$R= 5.58*10^{10}m$

7 0

3 years ago

A machine accelerates a 5 kg missile from rest to a speed of 5 km/s. The net force accelerating the missile 500,000 N. How long

Gnoma [55]

Final velocity = 5km/sec = 5000 m/sec
Initial velocity = 0, mass = 5kg and force = 500,000 N
F = m(Vf-Vi)/time
Time = m(Vf-Vi)/force = 5*5000/500000 = 0.05 seconds
So, it takes 0.05 sec to arrive at the speed of 5km/s.

3 0

3 years ago

Sometimes when we refer to carbon dioxide we write it as CO2 what is CO2

frez [133]

C stands for carbon. The O stands for oxygen. CO2 is one carbon atom and two oxygen atoms

7 0

2 years ago

The question below refers to the following graph.

wolverine [178]

I think ts 15 centimeters

8 0

3 years ago

Read 2 more answers