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Blizzard [7]
3 years ago
14

Which net ionic equation best represents the reaction that occurs when an aqueous solution of barium chloride is mixed with an a

queous solution of lithium sulfate?
Chemistry
1 answer:
vovangra [49]3 years ago
6 0

Answer : The net ionic equation will be:

Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The balanced molecular equation will be,

BaCl_2(aq)+Li_2SO_4(aq)\rightarrow 2LiCl(aq)+BaSO_4(s)

The complete ionic equation in separated aqueous solution will be,

Ba^{2+}(aq)+2Cl^-(aq)+2Li^+(aq)+SO_4^{2-}(aq)\rightarrow 2Li^+(aq)+2Cl^-(aq)+BaSO_4(s)

In this equation the species, Li^+\text{ and }Cl^{-} are the spectator ions.

By removing the spectator ions , we get the net ionic equation.

The net ionic equation will be:

Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)

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4 0
3 years ago
in which of the following aqueous solutions would you expect AgCl to have the HIGHEST solubility?a) Pure Waterb) 0.015 M NaClc)
kirill115 [55]

Answer:

Pure Water

Explanation:

The common ion effect describes the effect on ​equilibrium that occurs when a common ion (an ion that is already contained in the solution) is added to a solution. The common ion effect generally decreases ​solubility of a solute(Khan Academy).

NaCl, AgNO3, KCl, BaCl2 solutions all have a common ion with AgCl. As a result of this, AgCl will be much less soluble in these solvents than it is in pure water.

Therefore, AgCl will have the highest solubility in pure water compared to all the solutions listed above.

6 0
3 years ago
CaCO3(s) ∆→CaO(s) + CO2(g).
sveta [45]

Answer:

74.9%.

Explanation:

Relative atomic mass data from a modern periodic table:

  • Ca: 40.078;
  • C: 12.011;
  • O: 15.999.

What's the <em>theoretical</em> yield of this reaction?

In other words, what's the mass of the CO₂ that should come out of heating 40.1 grams of CaCO₃?

Molar mass of CaCO₃:

M(\text{CaCO}_3) = 40.078 + 12.011 + 3 \times 15.999 = 100.086\;\text{g}\cdot\text{mol}^{-1}.

Number of moles of CaCO₃ available:

\displaystyle n(\text{CaCO}_3) =\frac{m}{M} = \frac{40.1}{100.086} = 0.400655\;\text{mol}.

Look at the chemical equation. The coefficient in front of both CaCO₃ and CO₂ is one. Decomposing every mole of CaCO₃ should produce one mole of CO₂.

n(\text{CO}2) = n(\text{CaCO}_3)= 0.400655\;\text{mol}.

Molar mass of CO₂:

M(\text{CO}_2) = 12.011 + 2\times 15.999 = 44.009\;\text{g}\cdot\text{mol}^{-1}.

Mass of the 0.400655 moles of \text{CO}_2 expected for the 40.1 grams of CaCO₃:

m(\text{CO}_2) = n\cdot M = 0.400655 \times 44.009 = 17.632\;\text{g}.

What's the <em>percentage</em> yield of this reaction?

\displaystyle \textbf{Percentage}\text{ Yield} = \frac{\textbf{Actual}\text{ Yield}}{\textbf{Theoretical}\text{ Yield}}\times 100\%\\\phantom{\textbf{Percentage}\text{ Yield}} = \frac{13.2}{17.632}\times 100\%\\\phantom{\textbf{Percentage}\text{ Yield}} =74.9\%.

7 0
3 years ago
The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0 °c is 4.48. what is the value of ka for hbro?
Alex Ar [27]

____________________________________________________

Answer:

Your answer would be a). 2.0 × 10-9

____________________________________________________

Work:

In your question the "ph" of a 0.55 m aqueous solution of hypobromous acid temperature is at 25 degrees C, and it's "ph" is 4.48.

You would use the ph (4.48) to find the ka for "hbro"

[H+]

=

10^-4.48

=

3.31 x 10^-5 M

=

[BrO-]

or: [H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-]

Then you would find ka:

(3.31 x 10^-5)^2/0.55 =2 x 10^-9

____________________________________________________

<em>-Julie</em>

6 0
3 years ago
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