Answer:
The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.
Explanation:
The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:
<u>Where:</u>
<em>μ (l): is the chemical potential of 2-propanol in solution </em>
<em>μ° (l): is the chemical potential of pure 2-propanol </em>
<em>R: is the gas constant = 8.314 J K⁻¹ mol⁻¹ </em>
<em>T: is the temperature = 82.3 °C = 355.3 K </em>
<em>x: is the mole fraction of 2-propanol = 0.41 </em>
Therefore, the chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.
I hope it helps you!
2 C₁₇H₁₉NO₃ + H₂SO₄ → Product
Moles of H₂SO₄ = M x V(liters) = 0.0116 x 8.91/1000 = 1.033 x 10⁻⁴ mole
moles of morphine = 2 x moles of H₂SO₄ = 2.066 x 10⁻⁴
Mass of morphine = moles x molar mass of morphine = 2.066 x 10⁻⁴ x 285.34
= 0.059 g
percent morphine =
=
= 8.6 %
As a wave and also as a particle. This was proposed by Einstain and it is a theory.
Answer:
0.0646 mole.
Explanation:
The following data were obtained from the question:
Number of molecules = 3.89×10²² molecules
Number of mole =?
The number of mole present in 3.89×10²² molecules of CCl₄ can be obtained as follow:
From Avogadro's hypothesis:
6.02×10²³ molecules = 1 mole
Therefore,
3.89×10²² molecules = 3.89×10²² molecules × 1 mole / 6.02×10²³ molecules
3.89×10²² molecules = 0.0646 mole
Thus, 0.0646 mole is present in 3.89×10²² molecules of CCl₄.
