Answer:
Neutrons released during a fission reaction cause other nuclei to split
Hello,
I believe the answer is C. A and B say that it would help to change it but when we think about it data and opinions are not what people use to change a curriculum or program. Mainly they use surveys, which they didn't use here. Option D doesn't make any sense, data doesn't complement a program it supports some sort of theory which leads us to C. C is the only option where they use the data for effectiveness. Hope this helps!
<u>Answer:</u> The change in enthalpy for the given system is -642.8 kJ/mol
<u>Explanation:</u>
To calculate the change in enthalpy for given Gibbs free energy, we use the equation:
where,
= Gibbs free energy = -717.5 kJ/mol = -717500 J/mol (Conversion factor: 1 kJ = 1000 J)
= change in enthalpy = ?
T = temperature = 337 K
= change in entropy = 221.7 J/mol.K
Putting values in above equation, we get:
Hence, the change in enthalpy for the given system is -642.8 kJ/mol
Answer:
2,341g of CuSO₄.5H₂O
Explanation:
It is possible to assume all loses water comes from CuSO₄.5H₂O. Thus:
0,8445g H₂O (1mol H₂O / 18,015g) = 0,04688 moles of water.
As 1 mole of contains 5 moles of water, moles of CuSO₄.5H₂O are:
0,04688 moles H₂O × (1 mole CuSO₄.5H₂O / 5 moles H₂O) = 9,38x10⁻³ moles of CuSO₄.5H₂O
The molecular mass of CuSO₄.5H₂O is 249,69g/mol. Thus, mass of 9,38x10⁻³ moles of CuSO₄.5H₂O is:
9,38x10⁻³ moles of CuSO₄.5H₂O × (249,69g / mol) =
<em>2,341g of CuSO₄.5H₂O </em>is the maximum quantity of CuSO₄.5H₂O that could be in the sample.
I hope it helps!
