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zvonat [6]
3 years ago
9

What type of a reaction occurs when a sodium hydroxide solution is mixed with an acetic acid solution?

Chemistry
2 answers:
Harman [31]3 years ago
7 0

Answer:

C) acid-base neutralization

Explanation:

NaOH + CH₃COOH = CH₃COONa + H₂O

Break the solutions apart:

NaOH = Na⁺ + OH⁻

CH₃COOH = CH₃COO⁻ + H⁺

Combine the resulting solution after the reaction:

OH⁻ + H⁺ = H₂O

andrey2020 [161]3 years ago
7 0

Answer:

C) acid-base neutralization

Explanation:

In this type of titration, the equivalence point is at a pH greater than 7, due to weak acid anion hydrolysis, which is a hydrolysis that yields OH - ions.

Example: Titration of acetic acid with sodium hydroxide:

   CH3COOH + NaOH→ NaCH3COO + H2O

   NaCH3COO → Na+  + CH3COO–

At the equivalence point, all acetic acid was consumed and all NaOH was consumed. However, CH3COO– was produced. - pH is given by the solution of CH3COO - (weak acid anion hydrolysis) - Equivalence point: pH will be greater than 7. Since Na + is an acid-base neutral particle (strong base cation does not hydrolyze), only CH3COO– (weak acid anion) will undergo hydrolysis as shown below:

CH3COO- + H2O → CH3COOH  + OH-

OH ions will increase the pH of the solution as they will react with H3O + by the equation:

OH- + H3O+ → 2H2O

We can follow a practical example of the neutralization reaction in our daily lives: in the preparation of a simple lemonade. We know that the lemon has acidity, because it is present citric acid, what to do then to soften the acrid taste in the juice of this fruit? It is necessary to add a base, in this case it is common to use sodium bicarbonate (NaHCO3) to neutralize the acid action and make the lemonade more tasty.

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What is the concentration of H+ in 0.0025 M HClO4? What is the pH of the solution? What is the OH− concentration in the solution
alexandr402 [8]

Answer:

A. The concentration of H+ is 0.0025 M

B. The pH is 2.6

C. The concentration of OH- is 3.98x10^-12 M

Explanation:

We'll begin by writing the balanced

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HClO4 —> H+ + ClO4-

A. Determination of the concentration of H+ in 0.0025 M HClO4. This is illustrated below:

From the balanced equation above,

1 mole of HClO4 produced 1 mole of H+.

Therefore, 0.0025 M of HClO4 will also produce 0.0025 M of H+.

The concentration of H+ is 0.0025 M

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The pH of the solution can be obtained as follow:

The concentration of H+, [H+]

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pH =?

pH = - log [H+]

pH = - log 0.0025

pH = 2.6

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To obtain the concentration of OH-, we must first calculate the pOH of the solution. This is illustrated below:

pH + pOH = 14

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pOH =?

pH + pOH = 14

2.6 + pOH = 14

Collect like terms

pOH = 14 - 2.6

pOH = 11.4

Now, we can calculate the concentration of the OH- as follow:

pOH = - Log [OH-]

pOH = 11.4

11.4 = - Log [OH-]

- 11.4 = log [OH-]

[OH-] = anti log (- 11.4)

[OH-] = 3.98x10^-12 M

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3 years ago
Why do the metals Co, Rh, and Lr form octahedral complexes (rather than tetrahedral or square planar complexes)? Hint: Look at t
algol13

Explanation:

Octahedral complexes will be favoured over tetrahedral ones because:

It is more favourable to form six bonds rather than four

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Mg is balanced on both sides so move on to the next (put a 1 in the space). 

1Mg

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