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Ahat [919]
3 years ago
10

your friend wants to fly a kite over the water on the beach. which time would you go time a time c or time f

Chemistry
1 answer:
alexandr1967 [171]3 years ago
7 0

Answer:

uh time c

Explanation:

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Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 42. g of butane is m
taurus [48]

Answer:

127 grams of carbon dioxide

Explanation:

We need to determine the chemical equation first. Butane has a chemical formula of C_4H_{10}, oxygen is O_2, carbon dioxide is CO_2, and water is H_2O. The reactants are butane and oxygen and the products are carbon dioxide and water. So we write:

C_4H_{10}+O_2 ⇒ CO_2+H_2O

But remember! We need to balance this. Currently, there are 4 carbon atoms (C), 10 hydrogen atoms (H), and 2 oxygen atoms (O) on the left, while there are 1 carbon atom (C), 2 hydrogen atoms (H), and 3 oxygen atoms (O) on the right. Let's place a coefficient of 4 in front of the carbon dioxide and a coefficient of 5 on the water, so that we have equal numbers of carbon and hydrogen atoms on each side:

C_4H_{10}+O_2 ⇒ 4CO_2+5H_2O

However, we need to ensure that there are equal numbers of O atoms, as well. On the left, we have 2 and on the right we have 13, so let's put a coefficient of 6.5 on the oxygen:

C_4H_{10}+6.5O_2 ⇒ 4CO_2+5H_2O

Finally, multiply everything by 2 to get whole number coefficients:

2C_4H_{10}+13O_2 ⇒ 8CO_2+10H_2O

Ah, now we can actually get to the problem!

We need to determine the limiting reactant, so let's convert the 42 g of butane and 150 g of oxygen into moles of any product, say, carbon dioxide. To convert to moles, we need to find the molar mass of each compound.

The molar mass of butane is 4 * 12.01 + 10 * 1.01 = 58.14 g/mol, while the molar mass of oxygen is 2 * 16 = 32 g/mol. We can now set up the equations:

42 gC_4H_{10}*\frac{1molC_4H_{10}}{58.14gC_4H_{10}} *\frac{8molCO_2}{2molC_4H_{10}} =2.8896molCO_2

150 gO_2*\frac{1molO_2}{32gO_2} *\frac{8molCO_2}{13molO_2} =2.8846molCO_2

Clearly, we see that 2.8846 < 2.8896, which means that oxygen is the limiting reactant. In other words, the most products can be made when the oxygen is all used up.

Now let's finally convert moles of carbon dioxide into grams by multiplying by its molar mass, which is 12.01 + 2 * 16 = 44.01 g/mol:

2.8846molCO_2*\frac{44.01gCO_2}{1molCO_2} =127gCO_2

Notice that we have 3 significant figures because we had 3 significant figures at the start with 150. grams of oxygen.

<em>~ an aesthetics lover</em>

4 0
3 years ago
The volume of a gas at 17.5 psi decreases from 1.8L to 750mL. What is the new pressure of the gas in arm?
Maurinko [17]

Answer:

P₂ = 2.88 atm

Explanation:

Given data:

Initial volume of gas = 1.8 L

Final volume = 750 mL

Initial pressure = 17.5 Psi

Final pressure = ?

Solution:

We will convert the units first:

Initial pressure = 17.5  /14.696 = 1.2 atm

Final volume = 750 mL ×1L/1000L = 0.75 L

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.2 atm × 1.8 L =  P₂  ×0.75 L

P₂ = 2.16 atm. L/ 0.75 L

P₂ = 2.88 atm

4 0
3 years ago
Which of the following describes a reference point?
Vitek1552 [10]

Answer:

A

Explanation:

i think the answer is A

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How many electron domains does IF4+ have?
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I maybe wrong but i believe 36
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2 years ago
The mechanical advantage of the wedge increases as it gets _____.
OLEGan [10]
Do you have Answer Choices
6 0
3 years ago
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