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ankoles [38]
3 years ago
11

How many moles of water would you have if you had 3x10^24 molecules of

Chemistry
1 answer:
goldfiish [28.3K]3 years ago
5 0
I am going to be honest i’m good at chemistry but i need the point cause i need help on my history work
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A solution contains 6.21 g of ethylene glycol dissolved in 25.0 g of water. If water has a boiling point elevation constant of 0
timurjin [86]
Calculate first the number of moles of ethylene glycol by dividing the mass by the molar mass.
                           n = (6.21 g ethylene glycol) / 62.1 g/mol
                              n = 0.1 mol
Then, calculate the molality by dividing the number of moles by the mass of water (in kg).
                           m = 0.1 mol/ (0.025 kg) = 4m
Then, use the equation,
                       Tb,f = Tb,i + (kb)(m)
Substituting the known values,
                       Tb,f = 100°C + (0.512°C.kg/mol)(4 mol/kg)
                          <em>Tb,f = 102.048°C</em>
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3 years ago
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What is the octet rule?
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The Octet rule is a general rule of thumb that applies to most atoms. Basically, it states that every atom wants to have eight valence electrons in its outermost electron shell.


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3 years ago
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Which has a higher average speed of molecules 95 degrees Celsius or 95 degrees Fahrenheit ​
shutvik [7]

Answer:

95(ninety five) degrees Celsius

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Why potasium more reactive than lithium and sodium
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5 0
3 years ago
Calcular la cantidad de NaOH necesaria para preparar medio litro de disolución 2,5 N. (Dato: peso molecular del NaOH = 40 g/mol)
kolbaska11 [484]

Answer:

The amount of NaOH required to prepare a solution of 2.5N NaOH.

The molecular mass of NaOH is 40.0g/mol.

Explanation:

Since,

NaOH has only one replaceable -OH group.

So, its acidity is one.

Hence,

The molecular mass of NaOH =its equivalent mass

Normality formula can be written as:Normality=\frac{mass of solute NaOH}{its equivalent mass}  * \frac{1}{volume of solution in L} \\

Substitute the given values in this formula to get the mass of NaOH required.

2.5N=\frac{mass of NaOH}{40g/mol} *\frac{1}{1L} \\mass of NaOH=2.5N*40gmol\\                         =      100.0g

Hence, the mass of NaOH required to prepare 2.5N and 1L. solution is 100g

8 0
3 years ago
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