Question

1. A 225-L barrel of white wine has an initial free SO2 concentration of 22 ppm and a pH of 3.70. How much SO2 (in grams) should be added to the barrel to result in the required SO2 level

Answer 1

Answer:

The appropriate answer is "9.225 g".

Explanation:

Given:

Required level,

= 63 ppm

Initial concentration,

= 22 ppm

Now,

The amount of free SO₂ will be:

= $Required \ level -Initial \ concentration$

= $63-22$

= $41 \ ppm$

The amount of free SO₂ to be added will be:

= $41\times 225$

= $9225 \ mg$

∵ 1000 mg = 1 g

So,

= $9225\times \frac{1}{1000}$

= $9.225$

Thus,

"9.225 g" should be added.