Question

The free-body diagram of a crate is shown. A free body diagram with 4 force vectors. The first vector is pointing downward, labeled F Subscript g Baseline = negative 440 N. The second vector is pointing right, labeled F Subscript p Baseline = 176 N. The third vector is pointing upward, labeled F Subscript N Baseline = 440 N. The fourth vector is pointing left, labeled F Subscript f Baseline = negative 352 N. The up and down vectors are the same length. The right vector is shorter than the left vector. What is the net force acting on the crate? 352 N to the left 176 N to the left 528 N to the right 440 N to the right

Answer 1

The net force acting on the crate is determined as 176 N to the left.

Net force acting on the crate

The net force acting on the crate is calculated as follows;

∑F = F1 + F2 + F3 + F4

F(net) = -440y + 176x + 440y - 352x

F(net) = -176 x

The resultant force is pointing in negative x direction.

Thus, the net force acting on the crate is determined as 176 N to the left.

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