This question is incomplete, the complete question is;
Car B is rounding the curve with a constant speed of 54 km/h, and car A is approaching car B in the intersection with a constant speed of 72 km/h. The x-y axes are attached to car B. The distance separating the two cars at the instant depicted is 40 m. Determine: the angular velocity of Bxy rotating frame (ω).
Answer:
the angular velocity of Bxy rotating frame (ω) is 0.15 rad/s
Explanation:
Given the data in the question and image below and as illustrated in the second image;
distance S = 40 m
V
= 54 km/hr
V
= 72 km/hr
α = 100 m
now, angular velocity of Bxy will be;
ω
= V
/ α
so, we substitute
ω
= ( 54 × 1000/3600) / 100
ω
= 15 / 100
ω
= 0.15 rad/s
Therefore, the angular velocity of Bxy rotating frame (ω) is 0.15 rad/s
Answer: wavelength=velocity×period
Explanation:the relation between velocity, wavelength and period is
Wavelength=velocity×period
Answer:
The velocity at the nozzle at inlet
= 3584 
Explanation:
Pressure at inlet
= 1 ×
Pa
Temperature at inlet
= 518 ° c = 791 K
Mass flow rate =
= 88.7
Gas constant for carbon die oxide is R = 189 
Mass flow rate inside the nozzle is given by the formula =
×
×
⇒
= = 1 ×
Pa
⇒ R
= 791 × 189 = 149499 
⇒
= 0.0037 
Put all the above values in above formula we get,
⇒ 88.7 =
× 0.0037 × 
⇒
= 3584 
This is the velocity at the nozzle at inlet.
ANSWER:
(a) 1036 N
(b) -1036 N
(c) 2590 N
STEP-BY-STEP EXPLANATION:
Given:
Mc = 1400 kg
Mt = 560 kg
a = 1.85 m/s^2
(a)
Force by car on trailer:

(b)

(c)