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4 years ago

What would happen if you held the South Pole of one magnet near the North Pole of another magnet of the same size?

Physics

2 answers:

allsm [11]4 years ago

6 0

Answer:

(B) The magnets would be attracted to each other.

Explanation:

KiRa [710]4 years ago

4 0

The correct choice would be

(B) The magnets would be attracted to each other.

we know that like poles repel each other and unlike poles attract each other. hence when south pole of one magnet is placed near the north pole of other magnet, the two magnets attract each other due to interaction of magnetic fields of the two magnets. the magnetic field lines originating from north pole of one magnet ends at the south of other magnet

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Name at least three physical properties of the bowling ball.

HACTEHA [7]

The bowling ball is round in shape and red in color.

The bowling ball is smooth and hard.

*The shape of the bowling ball is round.

The color of the bowling ball is red.

The bowling ball is hard.

The bowling ball is smooth.

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3 years ago

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He was a priest who issued the Grito de Dolores, a call for a peasant rebellion in Mexico.

uranmaximum [27]

It was D. Miguel Hidalgo but i could be wrong..

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3 years ago

A roundabout is a type of playground equipment involving a large flat metal disk that is able to spin about its center axis. A r

Zina [86]

Answer:

116.1 kgm²/s

1.12718 rad/s

Decreases

Explanation:

m = Mass of girl = 43 kg

M = Mass of roundabout = 120 kg

v = Velocity of roundabout = 2.7 m/s

r = Radius of roundabout = 1 m = R

I = Moment of inertia

Her angular momentum

$L_i=mvr\\\Rightarrow L_i=43\times 2.7\times 1\\\Rightarrow L_i=116.1\ kgm^2/s$

Magnitude of angular momentum is 116.1 kgm²/s

Here the angular momentum is conserved

$L_f=L_i\\\Rightarrow I\omega=L_i\\\Rightarrow (\frac{1}{2}MR^2+mr^2)\omega=116.1\\\Rightarrow \omega=\frac{116.1}{\frac{1}{2}\times 120\times 1^2+43\times 1^2}\\\Rightarrow \omega=1.12718\ rad/s$

Angular speed of the roundabout is 1.12718 rad/s

Initial kinetic energy

$K_i=\frac{1}{2}mv^2\\\Rightarrow K_i=\frac{1}{2}43\times 2.7^2\\\Rightarrow K_i=156.735\ J$

Final kinetic energy

$K_f=\frac{1}{2}I\omega^2\\\Rightarrow K_f=\frac{1}{2}\times (\frac{1}{2}\times 120\times 1^2+43\times 1^2)\times 1.12718^2\\\Rightarrow K_f=65.43253\ J$

The overall kinetic energy decreases as can be seen. This loss is converted to heat.

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3 years ago

Explain the different methods that can be used to model the motion of an object.

Simora [160]

Answer:

You can describe the motion of an object by its position, speed, direction, and acceleration. An object is moving if its position relative to a fixed point is changing. idk if this helps.

Explanation:

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3 years ago

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What is the change in velocity of a 15 kg object that experiences a 5 N force for 0.3 seconds?

alukav5142 [94]

Hello!

Δv = 0.1 m/s

Use the equation F = m · a to solve for the acceleration:

5 = 15 · a

a = 1/3

The equation to solve for acceleration can be rewritten to solve for the change in velocity:

Δv / t = a

Δv = at

We are given the acceleration and time, therefore:

Δv = (1/3)(0.3)

Δv = 0.1 m/s

3 0

3 years ago