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pantera1 [17]
3 years ago
5

What would happen if you held the South Pole of one magnet near the North Pole of another magnet of the same size?

Physics
2 answers:
allsm [11]3 years ago
6 0

Answer:

(B) The magnets would be attracted to each other.

Explanation:

KiRa [710]3 years ago
4 0

The correct choice would be

(B) The magnets would be attracted to each other.

we know that like poles repel each other and unlike poles attract each other. hence when south pole of one magnet is placed near the north pole of other magnet, the two magnets attract each other due to interaction of magnetic fields of the two magnets. the magnetic field lines originating from north pole of one magnet ends at the south of other magnet

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In this image of Earth and the Moon from the Sim, what does the circle around Earth represent?
lidiya [134]

Answer: This is the orbit (of the moon around Earth).

An orbit is a circular/oval path that planets, moons, comets, etc follow with a "subject" in the middle. In this case, the circle is the orbit of the moon around Earth.

5 0
3 years ago
What do radio waves and microwaves have in common?
Tamiku [17]

Answer:

I Will say the Answer is A

Explanation:

5 0
2 years ago
Read 2 more answers
A hockey player hits a rubber puck from one side of the rink to the other. It has a mass of .170 kg, and is hit at an initial sp
Dimas [21]

By using third law of equation of motion, the final velocity V of the rubber puck is 8.5 m/s

Given that a hockey player hits a rubber puck from one side of the rink to the other. The parameters given are:

mass m =  0.170 kg

initial speed u = 6 m/s.

Distance covered s = 61 m

To calculate how fast the puck is moving when it hits the far wall means we are to calculate final speed V

To do this, let us first calculate the kinetic energy at which the ball move.

K.E = 1/2mU^{2}

K.E = 1/2 x 0.17 x 6^{2}

K.E = 3.06 J

The work done on the ball is equal to the kinetic energy. That is,

W = K.E

But work done = Force x distance

F x S = K.E

F x 61 = 3.06

F = 3.06/61

F = 0.05 N

From here, we can calculate the acceleration of the ball from Newton second law

F = ma

0.05 = 0.17a

a = 0.05/0.17

a = 0.3 m/s^{2}

To calculate the final velocity, let us use third equation of motion.

V^{2} = U^{2} + 2as

V^{2}  = 6^{2} + 2 x 0.3 x 61

V^{2} = 36 + 36

V^{2} = 72

V = \sqrt{72}

V = 8.485 m/s

Therefore, the puck is moving at the rate of 8.5 m/s (approximately) when it hits the far wall.

Learn more about dynamics here: brainly.com/question/402617

5 0
2 years ago
A worker pushes horizontally on a large crate with a force of 200 N, and the crate is moved 3.5 m. How much work was done in Jou
sattari [20]

Work = (force) x (distance) =

           (200 N) x (3.5 m)  =  <em>700 joules</em>


6 0
3 years ago
The speed of a 2.0-kg object changes from 30 m/s to 40 m/s during a 5.0-second time interval.
AnnyKZ [126]

Answer:

F = 2 * 30 / 5 = 12 N to stop forward motion

F = 2 * 40 / 5 = 16 N to accelerate to 90 degrees

(12^2 + 16^2)^1.2 = 20 N   average force applied

5 0
3 years ago
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