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Zina [86]
3 years ago
13

Which feature of a soundwave is related to pitch

Physics
2 answers:
elena-s [515]3 years ago
6 0

Answer:

loudness

Explanation:

both loudness and pitch are determined by intensity of a sound wave, though pitch has another factor known as <em><u>f</u></em><em><u>r</u></em><em><u>e</u></em><em><u>q</u></em><em><u>u</u></em><em><u>e</u></em><em><u>n</u></em><em><u>c</u></em><em><u>y</u></em>

almond37 [142]3 years ago
3 0

Answer:

Frequency

Explanation:

As we know that the characteristics of sound is as following

Loudness : loudness of sound depends on the amplitude of sound so  increasing the loudness will cause the amplitude to increase.

Quality of sound : Quality of sound depends on the type of waveform. For different waveform the quality of sound is also different.

Pitch of sound : Pitch depends on the frequency of the sound which means if the frequency of sound is more then its frequency will be more

the correct answer will be

Frequency

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Calcular la longitud del faldón de una Rampa de Acceso , que en planta tiene una longitud de 20 m y la pendiente es 27%.
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La longitud del faldón de la rampa es de 5.4 m.

 

La pendiente expresada en porcentaje sigue la siguiente ecuación:

m=\frac{y}{x}*100 (1)

Donde:

  • y es la elevacion de la rampa (faldón)
  • x es la longitud de la ramapa (20 m)

Sabemos que la pendiente es de 27%. Por lo tanto, usando la ecuación 1, despejamos y.

27=\frac{y}{20}*100

y=\frac{27*20}{100}

y=5.4\: m        

La longitud del faldón es 5.4 m

Pudes ver más sobre el tema aquí:

brainly.com/question/8906330

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3 years ago
A gamma ray and a microwave traveling in a vacuum have the same?
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They have the same speed 
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A 500 kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 30 N/m. The blo
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Answer:

x = 0.396 m

Explanation:

The best way to solve this problem is to divide it into two parts: one for the clash of the putty with the block and another when the system (putty + block) compresses it is   spring

Data the putty has a mass m1 and velocity vo1, the block has a mass m2 .  t's start using the moment to find the system speed.

Let's form a system consisting of putty and block; For this system the forces during the crash are internal and the moment is preserved. Let's write the moment before the crash

    p₀ = m1 v₀₁

Moment after shock

    p_{f} = (m1 + m2) v_{f}

   p₀ = p_{f}

   m1 v₀₁ = (m1 + m2) v_{f}

  v_{f} = v₀₁ m1 / (m1 + m2)

   v_{f}= 4.4 600 / (600 + 500)

  v_{f} = 2.4 m / s

With this speed the putty + block system compresses the spring, let's use energy conservation for this second part, write the mechanical energy before and after compressing the spring

Before compressing the spring

   Em₀ = K = ½ (m1 + m2) v_{f}²

After compressing the spring

   E_{mf} = Ke = ½ k x²

As there is no rubbing the energy is conserved

   Em₀ = E_{mf}

   ½ (m1 + m2) v_{f}² = = ½ k x²

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   x = 2.4 √ (11/3000)

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An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) whi
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Answer:

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