Question

If a net force of 25 N is exerted over a distance of 4 m to the right on a 2 kg mass initially at rest and moves it, what is the final velocity of the object? v = _____ m/s

Answer 1

Answer: 10 m/s

Given:

Force, F = 25 N

Initial velocity  $u=0 m/s^{2}$

Distance moved, s= 4 m

mass, m = 2 kg

Formula Used:

$F = ma$

where a is the acceleration.

equation of motion:

$2as=v^{2}-u^{2}$

First, we would calculate the acceleration from the formula for force.

$a= \frac{F}{m}=\frac{25}{2}m/s^{2}$

Using the equation of motion, we can find the final velocity now:

$2$×$\frac{25}{2}$×$4= v^{2}-0^{2}$

taking the square root on both sides and ignoring the negative sign:

v= 10 m/s