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vampirchik [111]
4 years ago
9

The average summer temperature in Anchorage is 69 degrees Fahrenheit If the daily temperature is normally distributed with a sta

ndard deviation of 7 degrees Fahrenheit what percentage of the time would be would the temperature be between 55 degrees Fahrenheit and 76 degrees Fahrenheit?
A. 34%
B.47.5%
C.68%
D.81.5%
E.99.7%
Mathematics
1 answer:
Lemur [1.5K]4 years ago
3 0
B i think is the answer
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I have litre of bottle of cola i drink 650 ml how much is left
TiliK225 [7]

There are 1000 ml in one liter if you drank 650 ml then:

1000 - 650 = 350

350 ml are left

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3 years ago
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Prove or disprove that the product of two irrational numbers is irrational
DanielleElmas [232]
Hi. The statement you gave is somewhat true, but not always. I disprove this and there are tons of websites that can help you with more in depth explanation. Have a good day.
6 0
3 years ago
Help me please please​
cupoosta [38]

Answer:

  (7, 5)

Step-by-step explanation:

AC is the resultant. Point C is 7 units right and 5 units up from point A. If those are what go in your boxes, the resultant is ...

  \displaystyle\left(\,7\,\above\,5\,\right)

_____

<em>Comment on the question</em>

Vectors can be represented a number of different ways. Components can be given in rectangular or polar form, and the presentation can be made as a row vector, column vector, sum of orthogonal unit vectors, and other ways. We assume this is supposed to be a column vector of the form ...

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7 0
3 years ago
A data scientist studying a manufacturing process classifies each item produced by the process as either Poor, Acceptable, or Ex
Genrish500 [490]

Answer:

0.214 ; 0.064 ; 0.3859 ; 0.9966 ; 0.135

Step-by-step explanation:

Given the distribution :

Poor ___ Acceptable ____ Excellent

0.25 _____ 0.6 _________ 0.15

The data scientist receives three items produced by the manufacturing process.

Find the chance that:

a. all of items are Acceptable

0.6 * 0.6 * 0.6 = 0.6^3 = 0.214

b. none of the items is Acceptable

P(not acceptable) = 1 - p(acceptable) = 1 - 0.6 = 0.4

0.4 * 0.4 * 0.4 = 0.4^3 = 0.064

c. at least one of the items is Excellent

P(atleast one) = 1 - P(none)

P(not excellent) = 1 - 0.15 = 0.85

P(none is excellent) = 0.85^3 = 0.614125

Hence,

P(atleast one is excellent) = 1 - 0.614125 = 0.3859

d. not all of the items are Excellent

P(not all) = 1 - p(All)

P(all excellent) = 0.15^3 = 0.003375

P(not all are excellent) = 1 - 0.003375 = 0.9966

e. there is one item of each class:

P(poor) * p(acceptable) * p(excellent) * (number of classes)!

0.25 * 0.6 * 0.15 * 3!

= 0.135

3 0
3 years ago
Choose the equation and the inequality needed to answer this question.
Flauer [41]

Answer:

Actually, what you said you have so far is not correct.  The 2 correct answers are the 1st one (x + y = 15) and the 5th one (15x + 10y > 180)

Step-by-step explanation:

If tutoring French is x hours and scooping ice cream is y hours and he is going to work 15 hours for sure doing both, then we can add them together to get that x hours + y hours = 15 hours, or put simply:  x + y = 15.

Now we are going to throw in the added fun of the money he makes doing each.  The thing to realize here is that we can only add like terms.  So looking at the equation above, we have x hours of tutoring and y hours of scooping, so if we want to add them, we will add those number of hours together to get the total number of hours he worked, which we know to be 15.  The same goes for money.  If we add money earned from tutoring to money earned from scooping, we need that to be greater than the money he wants to earn which is 180 at least.  Because he wants to earn MORE than $180. we use the ">" sign.  Since he earns $15 an hour tutoring, that expression is $15x; since he earns $10 an hour scooping, that expression is $10y.  Now add them together (and you CAN because they are both expressions relating dollars to dollars) and set the sum > $180:

$15x + $10y > $180.  That's why your answer is not correct.  Use mine (with the understanding that you care about why yours is wrong and mine is correct) and you'll be fine.

5 0
3 years ago
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