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kumpel [21]
3 years ago
10

If a fuse or circuit breaker directly opens a circuit when the current limit is reached, do overload heaters open and break the

circuit when their current limit is reached?
Physics
1 answer:
OLEGan [10]3 years ago
3 0

Answer:

No

Explanation:

No, overload heaters do not open to break the circuit  when their current limit is reached. These are safety device to prevent over heating.

Thermal overload relays in a motor are intended to protect the conductors (windings). Such safety devices are made to maintain the current flow in a circuit at a safety level so as to avoid overheating of the circuitry conductors. And the excess of current is often called as over current.

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. Maria walked 1.5 miles south to her house in 0.5 hours. What is her speed in miles per hour?
Simora [160]

1) 3 miles/Hour

The speed is defined as the distance covered divided by the time taken:

v=\frac{d}{t}

where

d = 1.5 mi is the distance

t = 0.5 h is the time taken

Substituting,

v=\frac{1.5}{0.5}=3 mi/h

2) 1.34 m/s south

Velocity, instead, is a vector, so it has both a magnitude and a direction. We have:

d=1.5 mi \cdot 1609 m/mi = 2414 m is the displacement in meters

t=0.5 h \cdot 3600 s/h =1800 s is the time taken in seconds

Substituting,

v=\frac{2414 m}{1800 s}=1.34 m/s

And the direction of the velocity is the same as the displacement, so it is south.

6 0
4 years ago
The rate at which energy is transferred is called a. joules. b. power. c. work. d. time.
Marrrta [24]
B. Power
I hope this helps you, have a great day!
7 0
3 years ago
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The relationship between the mass and volume of an object is its weight.<br> TRUE or FALSE?
Arturiano [62]
The answer is false.
5 0
3 years ago
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Plz help me with this ^^^
gogolik [260]
Assuming all the landmasses continue to move towards a sort of epicenter, large mountain ranges would appear in Africa and Europe.
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4 years ago
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A playground merry-go-round of radius R = 1.80 m has a moment of inertia I = 270 kg · m2 and is rotating at 8.0 rev/min about a
Arte-miy333 [17]

Answer:

\dot n = 6.042\,rpm

Explanation:

The final angle speed of the merry-go-round is determined with the help of the Principle of Angular Momentum Conservation:

(270\,kg\cdot m^{2})\cdot \left(8\,rpm\right) = [270\,kg\cdot m^{2}+(27\,kg)\cdot (1.80\,m)^{2}]\cdot \dot n

\dot n = 6.042\,rpm

3 0
3 years ago
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