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hichkok12 [17]
3 years ago
13

How do you make a sound wave’s pitch lower?

Physics
1 answer:
Rudik [331]3 years ago
7 0

Sound travels more slowly than light. Sound waves travel at the same speed, but vibrate in different ways. when sounds vibrate slowly they give a lower pitch

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Find the final temperature of 375 grams of tea (c = 4.184 J/g°C) if its initial temperature is 95°C just before it is placed in
Minchanka [31]

Answer:

the final temperature of the tea is 7.39⁰C.

Explanation:

Given;

mass of the tea, m = 375 g

specific heat capacity of the tea, C = 4.184 JJ/g°C

initial temperature of the tea, t₁ = 95°C

the final temperature of the tea, t₂ = ?

Energy lost by the refrigerator, Q = 137,460 J

The energy lost by the refrigerator is given by the following formula;

-Q = mc(t₂ - t₁)

-137,460 =375 x 4.184(t₂ - 95°C)

-137,460 = 1569(t₂ - 95°C)

t_2-95 = \frac{-137,460}{1569} \\\\t_2-95 = -87.61\\\\t_2 = -87.61 + 95\\\\t_2 = 7.39 \ ^0 C

Therefore, the final temperature of the tea is 7.39⁰C.

4 0
3 years ago
Can someone please help me?
IRINA_888 [86]
It might be to late but the answer is C
7 0
3 years ago
A bug walking on the circular rim of a flower
Mekhanik [1.2K]

Given parameters;

Time taken to complete a lap  = 8.667s

Radius of flower = 13.9cm

    convert to SI unit of m,  100cm = 1m

            13.9cm gives \frac{13.9}{100}   = 0.139m

Unknown  = speed

To solve this problem, we need to first find the circumference of the flower.

 Circumference of the circular flower  = 2 π r

    where r is the radius of the flower;

           Circumference  = 2 x 3.142 x 0.139 = 0.87m

Now to find the how fast the bug is travelling,

   Speed  = \frac{distance}{time}

Since the bug covered 1 lap, the distance is 0.87m

Now input the parameters and solve for speed;

    Speed  = \frac{0.87}{8.667}  = 0.1m/s

The bug is travelling at a speed of  0.1m/s

8 0
3 years ago
Hydrogen line spectrum lies entirely within visible range
mart [117]

No, that's silly.

You've got your Pfund series where electrons fall down to the 5th level,
your Brackett series where they fall to the 4th level, and your Paschen
series where they fall to the 3rd level.  All of those transitions ploop out
photons at Infrared wavelengths.

THEN next you get your Balmer series, where the electrons fall in
to the 2nd level.  Most of those are at visible wavelengths, but even
a few of the Balmer transitions are in the Ultraviolet.

And then there's the Lyman series, where electrons fall all the way
down to the #1 level.  Those are ALL in the ultraviolet. 
6 0
3 years ago
The gap between electrodes in a spark plug is 0.060 cm. Producing an electric spark in a gasoline-air mixture requires an electr
Mandarinka [93]

Answer:

The magnitude of minimum potential difference is 1800 V

Explanation:

Given:

Electric field E = 3 \times 10^{6} \frac{V}{m}

Gap between electrodes d = 0.060 \times 10^{-2} m

For finding the minimum potential difference,

  \Delta V = E \times d

  \Delta V = 3 \times 10^{6} \times 0.060 \times 10^{-2}

  \Delta V = 1800 V

Therefore, the magnitude of minimum potential difference is 1800 V

8 0
3 years ago
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