Answer:
hola estoy aquí para ayudar
Step-by-step explanation:hola
Answer:
If I'm correct the slop appears to be 3x or (3/1)x
Step-by-step explanation:
First of all we need to remember rise/run (y/x) and that we begin calculating the slope by starting at the first point we are given on the graph
This linear equation goes up or "rises" up 3 on the y-axis till it meets a specific x-value giving us our rise of 3. Next we check on our "run" over the x-axis, which we find to be 1. The rise will represent our numerator and the run will represent our denominator. Thus we have 3/1 or a slope of 3.
You can also calculate this by picking the first given point on our line and finding its x and y coordinates on the plane. Then we can locate another point on the line and find its x and y coordinates as well. We take these two points' coordinates and divide using the point-slope formula. (x1,y1)/(x2,y2). I can't clearly see the points on your graph otherwise I'd tell you how to complete the point-slope formula in this example. However, we can eyeball it by using the first method (which isn't always accurate so I recommend using the point-slope formula when you can).
Answer:
no answer sorry
Step-by-step explanation:
no answer sorry
Answer:
-3.5 meters per second
Step-by-step explanation:
Divide the distance by the time.
-17.5 meters / 5 seconds = -3.5 meters per second
Answer:
a. 30 meters per second
b. -10 meters per second
Step-by-step explanation:
a. Average rate of change for the height from 0 to 6.6 secs can be calculated using the formula, ![m = \frac{H(b) - H(a)}{b - a}](https://tex.z-dn.net/?f=%20m%20%3D%20%5Cfrac%7BH%28b%29%20-%20H%28a%29%7D%7Bb%20-%20a%7D%20)
Thus,
Where,
![a = 0, H(0) = 0](https://tex.z-dn.net/?f=%20a%20%3D%200%2C%20H%280%29%20%3D%200%20)
![b = 6.6, H(6.6) = 198](https://tex.z-dn.net/?f=%20b%20%3D%206.6%2C%20H%286.6%29%20%3D%20198%20)
Plug in the values into the formula:
![m = \frac{198 - 0}{6.6 - 0}](https://tex.z-dn.net/?f=%20m%20%3D%20%5Cfrac%7B198%20-%200%7D%7B6.6%20-%200%7D%20)
![m = \frac{198}{6.6}](https://tex.z-dn.net/?f=%20m%20%3D%20%5Cfrac%7B198%7D%7B6.6%7D%20)
![m = 30](https://tex.z-dn.net/?f=%20m%20%3D%2030%20)
b. Average rate of change for the height from 8.8 to 13.2 secs = tex] m = \frac{H(b) - H(a)}{b - a} [/tex]
Where,
![a = 8.8, H(8.8) = 44](https://tex.z-dn.net/?f=%20a%20%3D%208.8%2C%20H%288.8%29%20%3D%2044%20)
![b = 13.2, H(13.2) = 0](https://tex.z-dn.net/?f=%20b%20%3D%2013.2%2C%20H%2813.2%29%20%3D%200%20)
Plug in the values:
![m = \frac{0 - 44}{13.2 - 8.8}](https://tex.z-dn.net/?f=%20m%20%3D%20%5Cfrac%7B0%20-%2044%7D%7B13.2%20-%208.8%7D%20)
![m = \frac{-44}{4.4}](https://tex.z-dn.net/?f=%20m%20%3D%20%5Cfrac%7B-44%7D%7B4.4%7D%20)
![m = -10](https://tex.z-dn.net/?f=%20m%20%3D%20-10%20)