<h3> Hope this attachment helps u</h3>
The first relation gives two y-values for any given x-value (except x=6).
y² +x = 6 . . . . . is not a function
Answer: what i would do is add a zero
Step-by-step explanation:
hope that help u have a wonderful day
Sure.
Can you find a number that goes into both terms, 5k and 35 ?
How about 5 ?
(5k - 35) = 5 times (k - 7) .