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kotegsom [21]
3 years ago
12

Determine the value of the current in the solenoid so that the magnetic field at the center of the loop is zero tesla. Justify y

our answer.
Physics
1 answer:
sleet_krkn [62]3 years ago
3 0

Answer:

I will explain the concept of magnetic field and how it can be calculated.

Explanation:

The formula for magnetic field at the center of a loop is given as

B = μ_{o}I / 2R

where B is the magnetic field

R is the radius of the loop

I is the current

and μ_{o} is the magnetic permeability of free space which is a constant 4π × 10^{-7} newtons/ampere²

If the magnetic field at the center of the loop is 0, then μ_{o}I = 0

I = 0 which means there will be no current flow in the loop.

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Suggest two uses of pulleys.
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Answer: Elevators use pulleys to function.

A cargo lift system that allows for items to be hoisted to higher floors is a pulley system.

Explanation:

8 0
2 years ago
What is the oscillation period of your eardrum when you are listening to the A4 note on a piano (frequency 440 Hz)?
Contact [7]

The period is the inverse of the frequence:

T=\dfrac{1}{f}=\dfrac{1}{440}=0.0022\overline{72}

4 0
3 years ago
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A +13.4 nC charge is located at (0,9.4) cm and a -4.23 nC charge is located (4.99, 0) cm. Where would a -14.23 nC charge need to
antiseptic1488 [7]

In order to solve this problem, we will first need to find the electric field at the origin without the 3rd charge

E1 = (9x10^9)(13.4x10^-9)/(9.4x10^-2)^2 = 13648.7 V/m towards the negative y-axis

E2 = (9x10^9)(4.23x10^-9)/(4.99x10^-2)^2 = 15289.1 V/m towards the positive x-axis

The red arrow shows the direction of which the electric field points.

To make the electric field at the origin 0, we must find a location where q3 = the magnitude of q1 and q2

Etotal = sqrt(E1+E2) = 20494.97 V/m

E3 = 20494.97 = (9x10^9)(14.23x10^-9)/(d)^2

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4 0
11 months ago
A rocket in deep space has an empty mass of 220 kg and exhausts the hot gases of burned fuel at 2500 m/s. What mass of fuel is n
Scilla [17]

Answer:

Explanation:

Let fuel is released at the rate of dm / dt where m is mass of the fuel

thrust created on rocket

= d ( mv ) / dt

= v dm / dt

this is equal to force created on the rocket

= 220 dv / dt

so applying newton's law

v dm / dt = 220 dv / dt

v dm = 220 dv

dv / v = dm / 220

integrating on both sides

∫ dv / v    = ∫ dm / 220

lnv =  ( m₂ - m₁ ) / 220

ln4000 - ln 2500 = ( m₂ - m₁ ) / 220

( m₂ - m₁ ) = 220 x ( ln4000 - ln 2500 )

( m₂ - m₁ ) = 220 x ( 8.29  - 7.82 )

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8 0
3 years ago
If your face is 62 cm in front of a plane mirror, where is the image of your face located?
timurjin [86]

Answer:

62 cm is in front of the mirror

Explanation:

This is answers

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