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lys-0071 [83]
3 years ago
6

The most important part of physical fitness is. Strength. B muscular endurance c flexibility. D. Cardiovascular

Physics
1 answer:
solniwko [45]3 years ago
7 0
The answer is D. Cardiovascular
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If an object is placed 10cm in front of a converging lens that has a focal length of 15cm. What are the properties of the image?
Contact [7]

Answer:

Enlarged [Size]

Virtual and Erect [Nature]

On the same side of the lens as the object [Position]

Explanation:

7 0
3 years ago
Barry slides across an icy pond. The coefficient of kinetic friction between his
Soloha48 [4]

The force of friction acting on him is 122 N. The correct answer is option C

<h3>What is Friction ?</h3>

Friction is a force that opposes the motion of a static or a moving object.

Given that Barry slides across an icy pond. The coefficient of kinetic friction between his shoes and the ice is 0.15. If his mass is 83 kg

The given parameters are;

  • Mass m = 83 kg
  • Coefficient of kinetic friction μ = 0.15
  • Frictional force F_{r} = ?

The normal reaction N on the body = mg

N = 83 x 9.8

N = 813.4 N

The Frictional force formula is  F_{r} = μN

F_{r} = 0.15 x 813.4

F_{r} = 122.01 N

Therefore, the force of friction acting on him is 122 N approximately.

Learn more about Friction here: brainly.com/question/24338873

#SPJ1

4 0
2 years ago
Select the correct answer.<br> Which type of energy is thermal energy a form of
elena-s [515]
Kinetic energy. thermal energy (a low form of energy ) is a form of kinetic energy as it is produced as a result of motion of particles either if they vibrate at their position or they move along longer paths. Motion produces friction or resistance which leads to excitation and thus the heat is produced. The higher the motion of the particles, the higher would be the thermal energy.
7 0
3 years ago
Which is not an example of a scalar?<br><br> a. 2t/s<br> b. 3kg<br> c. 6.2m north<br> d. -100c
xxMikexx [17]
C because I’m a teacher
4 0
3 years ago
A 0.89 m aqueous solution of an ionic compound with the formula mx has a freezing point of -3.0 ∘c . van't hoff factor?
BigorU [14]

Answer is: V<span>an't Hoff factor (i) for this solution is 1,81.
Change in freezing point from pure solvent to solution: ΔT =i · Kf · b.
Kf - molal freezing-point depression constant for water is 1,86°C/m.
b -  molality, moles of solute per kilogram of solvent.
</span><span>b = 0,89 m.
ΔT = 3°C = 3 K.
i = </span>3°C ÷ (1,86 °C/m · 0,89 m).

i = 1,81.

5 0
4 years ago
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