All categories

3 years ago

Compare and contrast how wind and glaciers abrade rock

Physics

2 answers:

OLga [1]3 years ago

7 0

Glaciers move slow and abrade rocks faster

AysviL [449]3 years ago

3 0

Glaciers slow moving enormous masses knocking out great chunks of rock.
wind faster moving, more like sandpaper (sand storms in deserts ?)

You might be interested in

Two moles of neon gas at 25oC and 2.0 atm is expanded to 3 times the original volume while the pressure is reduced to 1.0 atm. F

bazaltina [42]

Answer:

The end temperature is 174 °C

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

So, being:

P= 2 atm
V=?
n= 2 moles
R= 0.082 $\frac{atm*L}{mol*K}$
T= 25 °C= 298 °K

and replacing:

2 atm*V= 2 moles* 0.082 $\frac{atm*L}{mol*K}$ *298 K

you get:

$V=\frac{2 moles* 0.082\frac{atm*L}{mol*K} *298 K}{2 atm}$

V= 24.436 L

Now, two moles of neon gas is expanded to 3 times the original volume while the pressure is reduced to 1.0 atm. Then you know:

P= 1 atm
V= 3*24.436 L=73.308 L

n= 2 moles
R= 0.082 $\frac{atm*L}{mol*K}$
T= ?

Replacing:

1 atm*73.308 L= 2 moles* 0.082 $\frac{atm*L}{mol*K}$ *T

Solving:

$T=\frac{1 atm*73.308 L}{2 moles* 0.082\frac{atm*L}{mol*K}}$

T= 447 °K= 174 °C (being 0°C=273 °K)

<u><em>The end temperature is 174 °C</em></u>

5 0

3 years ago

Which elements are metals?Check all that apply.

ELEN [110]

HG. Li. Re dnsdfjnjdfsnijfdsnjfnsdjifnijdsnfijdnsijfijs

3 0

3 years ago

If the period of a simple pendulum is T and you increase its length so that it is 4 times longer, what will the new period be?

goldfiish [28.3K]

Answer:

T' = 2T

Explanation:

The time period of a simple pendulum is given by the relation as follows :

$T=2\pi \sqrt{\dfrac{l}{g}}$

l is length of the pendulum

g is acceleration due to gravity

If the length is increased four time, new length is l' = 4l

So,

New time period is :

$T'=2\pi \sqrt{\dfrac{l'}{g}}\\\\T'=2\pi \sqrt{\dfrac{4l}{g}}\\\\T'=2\times 2\pi \sqrt{\dfrac{l}{g}}\\\\T'=2\times T$

So, the new time period is 2 times of the initial time period.

5 0

3 years ago

What is the relationship between matter and energy as it changes states of matter (phase changes?)

AlekseyPX

These energy exchanges are not changes in kinetic energy. They are changes in bonding energy between the molecules. If heat is coming into a substance during a phase change, then this energy is used to break the bonds between the molecules of the substance. The example we will use here is ice melting into water.

7 0

4 years ago

If the Hubble Space Telescope is 598 m above the surface of the Earth and is traveling at 7.56 x 103 m/s, how long does it take

viva [34]

Answer:

5069.04 seconds

Explanation:

The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.

It is given as:

$T = \sqrt{\frac{4\pi^2r^3 }{GM} }$