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The momentum of each cart is given by:
where
m is the mass of the cart
v is its velocity (at the bottom of the ramp)
To answer the problem, let's calculate the momentum of each of the 4 carts:
1)
2)
3)
4)
Therefore, the cart with greatest momentum is cart 3, so the right answer is
<span>- trial 3, because this trial has a large mass and a large velocity</span>
where
m is the mass of the cart
v is its velocity (at the bottom of the ramp)
To answer the problem, let's calculate the momentum of each of the 4 carts:
1)
2)
3)
4)
Therefore, the cart with greatest momentum is cart 3, so the right answer is
<span>- trial 3, because this trial has a large mass and a large velocity</span>
The temperature of the air in the open orang pipe has been altered by 18.73° C
The frequency of an open orang pipe is estimated by using the formula:
Then, the combination of the frequency of the tuning fork and the open orang pipe is:
These combinations of frequency produce 4 beats per sound.
i.e.
When it is altered, the beats first diminish and increase again by 4.
i.e.
If we equate both equations (1) and (2) together, we have:
However, from our previous knowledge, we understand that the velocity of an object varies directly proportional to the square root of its temperature.
Hence;
- when the temperature of the pipe = unknown ???
- the temperature of the open orang pipe = 15
∴
By squaring both sides, we have:
T = 306.726912 - 273
T ≅ 33.73 ° C
∴
The change in temperature ΔT = 33.73° C - 15° C
The change in temperature ΔT = 18.73° C
Learn more about wave frequency here: