If there is no friction, the force that moves the box forward horizontally must be matched by the same force.
If there is friction, then the force moving it forward = frictional force + the additional force you need to add.
Whatever phase of the moon Ike sees, he can expect to see
the same phase of moon again, after 29.53 days later.
Answer:
Diabetic Retinopathy is a form of diabetes that affects the eyes. It can be caused by damage to the retinas, and can cause permanent damage to the eyes, and even blindness. Initially the patient is asymptomatic and become more visibly affected in later stages. It can be treated if caught early, or in mild cases.
Explanation:
Answer: a) 0.04kW = 40W
b) 0.05
Explanation:
A)
Thermal efficiency of the power cycle = Input / output
Input = 10 kW + 14,400 kJ/min = 10 kW + 14,400 kJ/(60s) = 10 kW + 14,400/60 kW.
Output = 10 kW
Thermal Efficiency = Output / Input = 10kW / 250kW = 0.04KW = 40W
B)
Maximum Thermal Efficiency of the power cycle = 1 - T1/T2
Where T1 = 285kelvin
And T2 = 300kelvin
Maximum Thermal Efficiency = 1 - T1/T2 = 1 - 285/300 = 0.05
A) ![\omega = \frac{1}{\sqrt{LC}}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%7BLC%7D%7D)
The magnitude of the capacitive reactance is given by
![X_C = \frac{1}{\omega C}](https://tex.z-dn.net/?f=X_C%20%3D%20%5Cfrac%7B1%7D%7B%5Comega%20C%7D)
where
is the angular frequency
C is the capacitance
While the magnitude of the inductive capacitance is given by
![X_L = \omega L](https://tex.z-dn.net/?f=X_L%20%3D%20%5Comega%20L)
where L is the inductance.
Since we want the two reactances to be equal, we have
![X_C = X_L](https://tex.z-dn.net/?f=X_C%20%3D%20X_L)
So we find
![\frac{1}{\omega C}= \omega L\\\omega^2 = \frac{1}{LC}\\\omega = \frac{1}{\sqrt{LC}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Comega%20C%7D%3D%20%5Comega%20L%5C%5C%5Comega%5E2%20%3D%20%5Cfrac%7B1%7D%7BLC%7D%5C%5C%5Comega%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%7BLC%7D%7D)
B) 7449 rad/s
In this case, we have
is the inductance
is the capacitance
Therefore, substituting in the formula for the angular frequency, we find
![\omega=\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{(5.30\cdot 10^{-3}H)(3.40\cdot 10^{-6} F)}}=7449 rad/s](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7B1%7D%7B%5Csqrt%7BLC%7D%7D%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B%285.30%5Ccdot%2010%5E%7B-3%7DH%29%283.40%5Ccdot%2010%5E%7B-6%7D%20F%29%7D%7D%3D7449%20rad%2Fs)
C) ![39.5 \Omega](https://tex.z-dn.net/?f=39.5%20%5COmega)
Now we can us the formulas of the reactances written in part A). We have:
- Capacitive reactance:
![X_C = \frac{1}{\omega C}=\frac{1}{(7449 rad/s)(3.40\cdot 10^{-6}F)}=39.5 \Omega](https://tex.z-dn.net/?f=X_C%20%3D%20%5Cfrac%7B1%7D%7B%5Comega%20C%7D%3D%5Cfrac%7B1%7D%7B%287449%20rad%2Fs%29%283.40%5Ccdot%2010%5E%7B-6%7DF%29%7D%3D39.5%20%5COmega)
- Inductive reactance:
![X_L = \omega L=(7449 rad/s)(5.30\cdot 10^{-3}H)=39.5 \Omega](https://tex.z-dn.net/?f=X_L%20%3D%20%5Comega%20L%3D%287449%20rad%2Fs%29%285.30%5Ccdot%2010%5E%7B-3%7DH%29%3D39.5%20%5COmega)