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3 years ago

What would happen if the moon was hit by an asteroid

Physics

1 answer:

Semmy [17]3 years ago

8 0

If the moon was hit by an asteroid there would be a crater mark and possible movement.

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Wave A has a longer wavelength than wave B, but their amplitudes are the same. Which carries more energy?

dangina [55]

The answer to this question would be B.

8 0

3 years ago

Read 2 more answers

An airplane flies 1,592 miles east from phoenix, Arizona, to Atlanta, Georgia, in 3.68 hours. What is the average velocity of th

KiRa [710]

Answer:

433 mph

Explanation:

We know that

$Velocity =\frac{Distance}{Time }$ ...Eq(1)

Here,

Distance =1,592 miles

Time=3.68 hours

Putting the value of distance and Time in the Eq(1) We get

Velocity = $\frac{1592\ miles}{3.68\ hours}$

$Velocity = 432.608\ mph\\Velocity = 433 mph$

therefore Average velocity is 433 mph

3 0

3 years ago

You are sitting 3 m away from you friend who is watching a cartoon on his phone. How will the sound itensity change if your frie

Zinaida [17]

Answer:

Decreases by $3.6 \times 10^{-3}$ times

Explanation:

The intensity of a sound is defined as the energy of the sound that is flowing in an unit time through the unit area which is in the direction that is perpendicular to the direction of the sound waves movement.

The intensity of energy is described by the inverse square law. It states that the intensity varies inversely with the distance square of the distance.

In other words, the sound intensity decreases as inversely proportional to the squared of the distance. i.e. $\frac{1}{r^2}$

In the context when the distance was 3 m, the intensity of the sound was = $\frac{1}{9}$

But when the distance became 6 cm or 0.06 m, the sound intensity decreases by = $\frac{1}{0.06^2}$

= $3.6 \times 10^{-3}$ times

3 0

3 years ago

a projectile is fired in such away that its horizontal range is equal to three times its naximum height.what is the angle of pro

finlep [7]

Answer:

$\theta=53.13^o$

Explanation:

<u>2-D Projectile Motion</u>

In 2-D motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration, while the acceleration in the vertical direction is always the acceleration due to gravity. The basic formulas for this type of movement are

$V_x=V_{ox}=V_ocos\theta$

$V_y=V_{oy}-gt=V_osin\theta-gt$

$x=V_{ox}t$

$\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}$

$\displaystyle x_{max}=\frac{2V_{ox}V_{oy}}{g}$

$\displaystyle y_{max}=\frac{V_{oy}^2}{2g}$

The projectile is fired in such a way that its horizontal range is equal to three times its maximum height. We need to find the angle \theta at which the object should be launched. The range is the maximum horizontal distance reached by the projectile, so we establish the base condition:

$x_{max}=3y_{max}$