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katovenus [111]
3 years ago
5

A chemist is using radiation with a frequency of 6.0 x 10^13 Hz

Chemistry
1 answer:
kirza4 [7]3 years ago
4 0

Answer:

λ = 0.5×10⁻⁵ m

E = 39.78×10⁻²¹ J

The given radiation is gamma ray.

Explanation:

Given data:

Frequency of radiation = 6.0 ×10¹³ Hz

Wavelength of radiation = ?

Type of radiation = ?

Energy of radiation = ?

Solution:

Formula:

speed of light = wavelength × frequency

3 ×10⁸ m/s = λ × 6.0 ×10¹³ Hz

Hz = s⁻¹

λ = 3 ×10⁸ m/s /  6.0 ×10¹³  s⁻¹

λ = 0.5×10⁻⁵ m

Energy of radiation:

E = hf

h = planck's constant

f = frequency

E = 6.63×10⁻³⁴ j.s × 6.0 ×10¹³  s⁻¹

E = 39.78×10⁻²¹ J

The given radiation is gamma ray.

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A gaseous mixture of o2 and n2 contains 35.8 % nitrogen by mass. what is the partial pressure of oxygen in the mixture if the to
lubasha [3.4K]
The partial pressure is the amount of linguistic compound there is which makes the lagitude of the element 64.663
5 0
3 years ago
A gas has a volume of 50.0 cm3 at a temperature of -73°c. what volume would the gas occupy at a temperature of -123°c if the pre
vaieri [72.5K]

Boyle’s Law illustrates the inverse relationship of volume and pressure. It follows the formula  p1V1 = P2V2 , where P1V1 denotes initial pressure and volume  and P2V2 denotes values of pressure and  volume.

Now, let us work out for what is asked above.
a. if the pressure is doubled
50.0 p = V x 2p 
V = 50.0 p / 2p

= 50.0 /2

= 25.0 m^3 
b. if the pressure is cut in half
50.0 p = V x p/2 
100 p = V x p 
V = 100 m^3 
c. if the pressure is tripled
50.0 p = V x 3p 
V = 50.0 p / 3p

= 50.0 /3

=16.7 m^3 

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7 0
2 years ago
How many grams of potassium sulphate are formed when 49g of sulphuric acid in solution are neutralised by potassium hydroxide?
Katena32 [7]
C - keep counting to the atoms
6 0
2 years ago
A 6.000L tank at 19.2°C is filled with 18.0g of carbon monoxide gas and 10.6g of chlorine pentafluoride gas. You can assume both
Jobisdone [24]

Answer:

Total pressure: 2.89 atm

Mole fraction CO: 0.88

Partial pressure CO: 2.56 atm

Mole fraction ClF₅: 0.12

Partial pressure ClF₅: 0.33 atm

Explanation:

We should apply the Ideal Gases Law to solve this:

P . V = n . R . T

We need n, which is the total moles for the mixture

Total moles = Moles of CO + Moles of ClF₅

Moles of CO = mass of CO / molar mass CO → 18 g/28 g/mol = 0.643 mol

Moles of ClF₅ = mass of ClF₅ / molar mass ClF₅ → 10.6g/ 130.45 g/m = 0.0812 mol

0.643 mol + 0.0812 mol → 0.724 moles in the mixture

So we have the total moles so with the formula we would know the total pressure.

P . 6L = 0.724 mol . 0.082L.atm/mol.K . 292.2K

P = ( 0.724 mol . 0.082L.atm/mol.K . 292.2K) / 6L

P = 2.89 atm

Mole fraction is defined as the quotient between the moles of gas over total moles, and it is equal to partial pressure of that gas over total pressure

Moles of gas X /Total moles = Partial pressure of gas X/Total pressure

(Moles of gas X / Total moles) . Total pressure = Partial pressure of gas X

Mole fraction CO = 0.643 / 0.724 = 0.88

Partial pressure CO = 0.88 . 2.89 atm → 2.56 atm

Mole fraction ClF₅ = 0.0812 / 0.724 = 0.12

Partial pressure ClF₅ = 0.12 . 2.89 atm → 0.33 atm

5 0
3 years ago
Please help I really appreciate it thank you ❤️
Feliz [49]

II. sulfur (S) and carbon (C)

and

III. fluorine (F) and oxygen (O)

will form covalent bonds, so the answer will be:

e. II and III

Explanation:

To know is what type of bond is formed between atoms we need to look at the electronegativity difference between the atoms.

If the electronegativity difference is less than 0.4 there is a nonpolar covalent bond.

If the electronegativity difference is between 0.4 and 1.8 there is a polar covalent bond. (if is a metal involved we consider the bond to be ionic)

If the electronegativity difference is greater then 1.8 there is an ionic bond.

We have the following cases:

I. lithium (Li) and sulfur (S)

electronegativity difference = 2.5 (S) - 1 (Li) = 1.5 but because there is a metal involved the bond will be ionic

II. sulfur (S) and carbon (C)

electronegativity difference = 2.5 (S) - 2.5 (C) = 0 so the bond will be nonpolar covalent

III. fluorine (F) and oxygen (O)

electronegativity difference = 4 (F) - 3.5 (O) = 0.5 so the bond will be polar covalent bond.

Learn more about:

covalent and ionic bonds

brainly.com/question/1802971

#learnwithBrainly

3 0
3 years ago
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