Antimony pentafluoride has a formula of SbF5. What is the percent composition of Sb in this molecule

Chemistry

1 answer:

Akimi4 [234]2 years ago

7 0

Answer:

56.17% is percent composition of Sb in the molecule

Explanation:

Percent composition is the percent in mass of each element present in a particular molecule.

In SbF₅, there is 1 mole of Antimony -Molar mass: 121.76g- per 5 moles of fluorine -Molar mass: 19g/mol-. In a basis of 1 mole, the mass of Sb and F is:

1mol * (121.76g/mol) = 121.76g

1 mol SbF₅ = 5 moles F * (19g / mol) = 95g

<em>Total mass:</em>

121.76g + 95g = 216.76g

And percent composition of Sb:

121.76g / 216.76g * 100 =

<h3>56.17% is percent composition of Sb in the molecule</h3>

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