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Vaselesa [24]
3 years ago
5

Can you help me with these physics questions

Physics
1 answer:
Andre45 [30]3 years ago
5 0

Answer:

xccccccccccccccccZd sdv ds

Explanation:

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A 0.5 kg ball moves in a circle that is 0.4 m in radius at a speed of 4.0 m/s. Calculate the force exerted on the ball.
blsea [12.9K]

Answer:

Explanation:

Given a ball of mass m= 0.5kg

The ball moves in as circle of radius r= 0.4m

Speed of the ball is v = 4m/s

Centripetal force is exerted on ball and it is given as

Fc = m•ac

ac is centripetal acceleration and it is given as

ac = v²/r

Then,

Fc = mv²/r

Fc = 0.5 × 4²/0.4

Fc = 20N.

The force exerted on the ball is 20N

5 0
3 years ago
A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 800 N on him. The
uysha [10]

Answer:

f = 692 N

Explanation:

given data:

f =800N

a =1.2 m s^{2}

m= 90 kg

from newton's second law

net force F_{net} =\sum F = F_1 +F_2 +..... = ma

therefore we have from above equationF_{net} = F -f = ma

ma =F - f

putting all value to get force of friction

1.2*90 = 800 - f

f = 692 N

8 0
3 years ago
In making the determination that bullets, shells, or cartridge cases were fired from a specific weapon, the criminalist would us
ss7ja [257]

Answer:

Comparison Microscope

Explanation:

The Comparison Microscope allows for comparison between two objects or samples by placing them side by side.

It is primarily used in criminology for ballistics which makes it ideal to find out if bullets, shells, or cartridge cases were fired from a specific weapon.

7 0
3 years ago
A vertical wire carries current in the upward direction. an electron is traveling parallel to the wire. what is the angle α betw
Luden [163]
Angle α between the velocity of theelectron and the magnetic field of the wire will be 90 degree
7 0
3 years ago
A very long wire generates a magnetic field of 0.0020x 10^-4 T at a distance of 10 mm. What is the magnitude of the current? A)
zimovet [89]

Answer:

2*10^-<em>5</em>

Explanation:

<em>B=</em><em>I</em><em>L</em>

<em>I=</em><em>B</em><em>/</em><em>L</em>

<em>I=</em><em>0</em><em>.</em><em>0</em><em>0</em><em>2</em><em>0</em><em>*</em><em>1</em><em>0</em><em>^</em><em>-</em><em>4</em><em>/</em><em>1</em><em>0</em>

<em>I=</em><em>2</em><em>*</em><em>1</em><em>0</em><em>^</em><em>5</em>

6 0
3 years ago
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