An electron with a speed of 1.7 × 107 m/s moves horizontally into a region where a constant vertical force of 4.9 × 10-16 N acts
on it. The mass of the electron is 9.11 × 10-31 kg. Determine the vertical distance the electron is deflected during the time it has moved 29 mm horizontally.
2 answers:
Answer:
y = 77.74 10⁻⁵ m
Explanation:
For this exercise we can use Newton's second law
F = m a
a = F / m
a = 4.9 10⁻¹⁶ / 9.1 10⁻³¹
a = 0.538 10¹⁵ m / s
This is the vertical acceleration of the electron.
Now let's use kinematics to find the time it takes to move the
x= 29 mm = 29 10⁻³ m
On the x axis
v = x / t
t = x / v
t = 29 10⁻³ / 1.7 10⁷
t = 17 10⁻¹⁰ s
Now we can look for vertical distance at this time.
y = t + ½ a t²
y = 0 + ½ 0.538 10¹⁵ (17 10⁻¹⁰)²
y = 77.74 10⁻⁵ m
You might be interested in
Answer:
The Hydrostatic force is
The location of pressure center is
Explanation:
From the question we are told that
The height of the gate is
The weight of the gate is
The height of the water is
The density of water is
Note used for height of water and height of gate immersed by water since both have the same value
The area of the gate immersed in water is mathematically represented as
substituting values
The hydrostatic force is mathematically represented as
Where
So
The center of pressure is mathematically represented as
Where is the moment of inertia of the gate which mathematically represented as
The is the height of gate immersed in water
Thus
Complete Question
The speed of a transverse wave on a string of length L and mass m under T is given by the formula
If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string
Answer:
Explanation:
From the question we are told that
Speed of a transverse wave given by
Maximum Tension is
Generally making subject from the equation mathematically we have
Therefore the Linear mass in terms of Velocity is given by