Answer:
v = 17.66 m/s
Explanation:
As we know that the lower end of the pole is fixed in the ground and it start rotating about that end
so here we can say that the gravitational potential energy of the pole will convert into rotational kinetic energy of the pole about its one end
so we have

so we have

now we have


now the speed of the other tip of the pole is given as


Answer:
a) 51.8 m, b) 27.4 m/s, c) 142 m
Explanation:
Given:
v₀ = 42.0 m/s
θ = 60.0°
t = 5.50 s
Find:
h, v, and H
a) y = y₀ + v₀ᵧ t + ½ gt²
0 = h + (42.0 sin 60.0) (5.50) + ½ (-9.8) (5.50)²
h = 51.8 m
b) vᵧ = gt + v₀ᵧ
vᵧ = (-9.8)(5.5) + (42.0 sin 60.0)
vᵧ = -17.5 m/s
vₓ = 42.0 cos 60.0
vₓ = 21.0 m/s
v² = vₓ² + vᵧ²
v = 27.4 m/s
c) vᵧ² = v₀ᵧ² + 2g(y - y₀)
0² = (42.0)² + 2(-9.8)(H - 51.8)
H = 142 m
This is because the diagram represented isotopes of Nitrogen. Isotopes are forms of an element with an equal number of protons but different number of neutrons.
Answer:
The amount of charge is "0.117 C" i.e., option A.
Explanation:
The given values are:
Force,
= 35 N
Electric field,
= 300 N/C
Charge,
q = ?
As we know,
⇒ 
On substituting the given values in the above formula, we get
⇒ 
⇒ 
⇒ 
1) Let's call

the speed of the southbound boat, and

the speed of the eastbound boat, which is 3 mph faster than the southbound boat. We can write the law of motion for the two boats:


2) After a time

, the two boats are

apart. Using the laws of motion written at step 1, we can write the distance the two boats covered:


The two boats travelled in perpendicular directions. Therefore, we can imagine the distance between them (45 mi) being the hypotenuse of a triangle, of which

and

are the two sides. Therefore, we can use Pythagorean theorem and write:

Solving this, we find two solutions. Discarding the negative solution, we have

, which is the speed of the southbound boat.