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nikdorinn [45]
3 years ago
5

Why should a hypothesis be testable?

Chemistry
1 answer:
Ierofanga [76]3 years ago
4 0
A. It must be testable in order to be found true or false.
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What causes the seasonal changes viewed in the night sky?
jonny [76]

Answer:

If you look at the night sky different

times of the year you see different

constellation.This change due to the

motion of the earth in it's orbit around

the sun.The shift of the sky is really

the motion of the earth around the sun.

Explanation:

Hope it helps

8 0
3 years ago
Read 2 more answers
How do you do empirical formula
mihalych1998 [28]

Answer:

ez

Explanation:

Step 1: Obtain the mass of each element present in grams. Element % = mass in g = m.

Step 2: Determine the number of moles of each type of atom present. ...

Step 3: Divide the number of moles of each element by the smallest number of moles. ...

Step 4: Convert numbers to whole numbers.

7 0
3 years ago
In this lab, you are to carry out the formation of a Grignard reagent from 1-bromo-benzene andits subsequent reaction with solid
yan [13]

Answer:

(A). C6H5Br + Mg(in ether) -----------> C6H5MgBr.

(B). C6H5MgBr + O = C = O -----------> C6H5-COO^- Mg^+ Br.

(C). C6H5-COO^- Mg^+ Br + HCl --------> C6H5-COOH + Mg^+Br(OH).

PRODUCTS=> C6H5-COOH and Mg^+Br(OH).

Explanation:

A Grignard reagent is a reagent that/which is an organometallic compound that is R -Mg- X. The R = alkyl, vinyl or allyl and the X = halogens.

It must be noted that an important reaction of Grignard reagent is its reaction with compounds containing the Carbonyl that is -CO functional group and this kind of Reaction is known as a Grignard Reaction.

So, in this question we are told that;

=> "1-bromo-benzene andits subsequent reaction with solid carbon dioxide (CO2) followed by acidic workup (using HCl asthe acid). "

Thus;

(A). C6H5Br + Mg(in ether) -----------> C6H5MgBr.

(B). C6H5MgBr + O = C = O -----------> C6H5-COO^- Mg^+ Br.

(C). C6H5-COO^- Mg^+ Br + HCl --------> C6H5-COOH + Mg^+Br(OH).

5 0
4 years ago
jamie is not sure a new medication will work because it has not had a large test group. Is jamie being creative?
Georgia [21]

Answer:

yes because I wouldn't do it

7 0
3 years ago
What would the % p, on the npk ratio, be reported as for a 100g sample containing 7.5g of phosphorous?
kati45 [8]
When the concentration is expressed in percentage, you simply have to divide the amount of substance to the total amount of the mixture, then multiply it by 100. In this case, when you want to find the percentage of P in the sample, the solution is as follows:

%P = 7.5 g/100 g * 100 =<em> 7.5%</em>
6 0
3 years ago
Read 2 more answers
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