Answer:
Bohrium (Niels Bohr)
Curium (Marie and Pierre Curie)
Einsteinium (Albert Einstein
The answer is the second option
Answer:
Fe
Explanation:
The cell potential is:
ΔE°cell = E°red(red) - E°red(oxid)
Where, E°red(red) is the reduction potential of the substance that is reducing, and E°red(oxid) is the reduction potential of the substance that is oxidizing. For the reaction be spontaneous and happen, ΔE°cell > 0.
The reduction takes place in the cathode, which is the negative pole, and the oxidation in the anode, which is the positive pole. So, the electrons flow from the positive pole to the negative pole (anode to cathode).
Then, if the voltmeter measured a negative potential, it means that is was attached incorrectly. So, the anode is Fe.
Answer:
FCI=88.0818 MM≅88 MM
Explanation:
Empirical correlation based on the work of Bridgwater and Mumford (1979):
For Liquid or solid phase Plants:
F<60,000 tonne/yr Eq (1)
F≥60,000 tonnes/yr Eq (2)
Where:
N is the number of functional units
F is the process throughput tonnes/yr
In our case F=40,000 tonne/yr <60,000 tonne/yr, We are going to use Eq (1)
F<60,000 tonne/yr
N=8, F=40,000 tonne/yr
FCI=88.0818 MM≅88 MM
