Given Information:
Resistance of circular loop = R = 0.235 Ω
Radius of circular loop = r = 0.241 m
Number of turns = n = 10
Voltage = V = 13.1 V
Required Information:
Magnetic field = B = ?
Answer:
Magnetic field = 0.00145 T
Explanation:
In a circular loop of wire with n number of turns and radius r and carrying a current I induces a magnetic field B
B = μ₀nI/2r
Where μ₀= 4πx10⁻⁷ is the permeability of free space and current in the loop is given by
I = V/R
I = 13.1/0.235
I = 55.74 A
B = 4πx10⁻⁷*10*55.74/2*0.241
B = 0.00145 T
Therefore, the magnetic field at the center of this circular loop is 0.00145 T
Memorize this and you'll be able to do ALL of these: <em>1 kg = 1,000 g</em>
So if you have some grams, divide the number by 1,000 to get kilograms.
1,000 g = 1.000 kg
500 g = 0.500 kg
100 g = 0.100 kg
50 g = 0.050 kg
20 g = 0.020 kg
10 g = 0.010 kg
Answer:
A vacuum would have been created. I hope this helps have a great day
Answer:
Value of electric field along the axis and equitorial axis
and
respectively.
Explanation:
Given :
Distance between charges , 
Magnitude of charges , 
Dipole moment , 
Case A) (x,y) = (12.0 cm, 0 cm) :
Electric field of dipole in its axis ,

Putting all values and 
We get , 
Case B) (x,y) = (0 cm, 12.0 cm) :
Electric field of dipole on equitorial axis ,

Putting all values and
We get , 
Hence , this is the required solution.
Answer:
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