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pentagon [3]
2 years ago
14

Two children, A and B, fire identical 10.0g all bearings from a catapult. the elastic band of each catapult extended by 0.10m an

d then released to fire the ball bearings. Child A's elastic band has a spring constant of 144N/m. calculate the energy transferred to the kinetic energy store of the child A's ball bearing.
thanks soo much (:

WORTH 50 PTS​
Physics
1 answer:
sergiy2304 [10]2 years ago
6 0

Answer:

The speed decreases and the frequency remains the same.

Explanation:

Mark me as brainliest, please?

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A 75 kV x-ray machine gives an exposure of 200 mR for a 0.2-sec chest x-ray exam.
pashok25 [27]

Explanation:

Given that,

Potential = 75 kV

Exposure = 200 mR

Time = 0.2 sec

We need to calculate the x-ray fluence during this chest x-ray exam

Using formula of fluence

x-ray\ fluence=exposure\times time

Put the value into the formula

x-ray\ fluence=200\times0.2

x-ray\ fluence=40\ mRs

We need to calculate the energy fluence

Using formula of energy fluence

E_{f}=40\times10^{-3}\times75\times10^{3}

E_{f} = 3000\ J

We need to calculate dose -equivalent delivered to the bone, muscle, and fat

Using formula of dose

D=\dfrac{E}{t}

Where, D = dose

E = energy

t = time

Put the value into the formula

D=\dfrac{3000}{0.2}

D=15.0\ kJ

Hence, This is the required solution.

7 0
3 years ago
In an experiment conducted using the Young's double-slit apparatus, the separation between the slits is 20 µm. A first-order con
jeka57 [31]
To solve this problem, we use the formula
λ = s sin θ
where s is the separation and θ is the angle interference
So,
λ = 20 x 10^-6 sin 2.5
λ = 8.72 x 10^-7 m

The required angle for the fourth order bright fringe is
θb = sin⁻¹ (4λ / s) = sin⁻¹ (4 (8.72 x 10^-7 m)/ 20 x 10^-6 ) = 10.04°

The required angle for the fourth order dark fringe is
θd = sin⁻¹ (4.5 λ / s) = sin⁻¹ (4.5 (8.72 x 10^-7 m)/ 20 x 10^-6 ) = 11.31°
6 0
3 years ago
Help!! ASAP plz
VashaNatasha [74]
Can you include an image of the object and it’s dimensions?
4 0
3 years ago
If a 20 gram bird and a 0.001 gram mosquito are moving at the same speed, which has the higher kinetic energy?why?
MissTica

Answer:

The bird has 20,000 times higher kinetic energy than the mosquito.

Explanation:

The formula for kinetic energy shows that the amount of energy is proportional to the mass:

E_k=\frac{1}{2}mv^2

The velocity of both objects being the same, the mass is the determiner. The ratio of the kinetic energy of the bird and the mosquito then becomes the ratio of their masses, i.e., 0.02kg/0.00001kg. The bird's energy is 20,000 times higher than that of the mosquito. This proportion becomes more believable if you imagine the event of a distracted errant bird colliding with your head, versus a confused mosquito colliding with your head.

8 0
3 years ago
g An object with mass m=2 kg is completely submerged, and tethered, to the bottom of a large body of water. If the density of th
Anit [1.1K]

Answer:

The tension in the rope is 20 N

Solution:

As per the question:

Mass of the object, M = 2 kg

Density of water, \rho_{w} = 1000\ kg/m^{3}

Density of the object, \rho_{ob} = 500\kg/m^{3}

Acceleration due to gravity, g = 10\ m/s^{2}

Now,

From the fig.1:

'N' represents the Bouyant force and T represents tension in the rope.

Suppose, the volume of the block be V:

V = \frac{M}{\rho_{ob}}              (1)

Also, we know that Bouyant force is given by:

N = \rho_{w}Vg

Using eqn (1):

N = \rho_{w}\frac{M}{\rho_{ob}}g

N = 1000\frac{2}{500}\times 10 = 40\ N

From the fig.1:

N = Mg + T

40 = 2(10) + T

T = 40 - 20 = 20 N

N = \rho_{w}Vg

3 0
3 years ago
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